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Anika [276]
3 years ago
8

A gardener uses 3 of a liter of water to water 7 of a garden.

Mathematics
1 answer:
arsen [322]3 years ago
8 0
Im not fully correct but i think you just multiply 3 x7= 21
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I really need help with this​
vova2212 [387]
The correct answer to this question is B.
8 0
3 years ago
Helppppppppppppppppppppppppppppppppppp
skad [1K]

Answer:

The answer would be 7 I hope this helps! : )

4 0
3 years ago
Read 2 more answers
Jenna and Becca were both selling cookies door to door. Jenna sold 8 boxes of cookies for every 3 boxes of cookies Becca sold. C
LenaWriter [7]
Answer:
Jenna sold 280 boxes, Becca sold 105 boxes.

Step-by-step explanation:
For every 3 boxes B sold, J sold 8 boxes and ended with a total of 385 boxes sold.
3b+8j=385
From how the question is asked, we can assume that each round of sales would equal 11 total sales. (3b+8j=11)
Knowing the sales take place in intervals of 11, we can solve the problem by doing 385/11.
385/11=35
Finally, with 35 rounds of sales happening and knowing Jenna sells 8 while Becca sells 3 at each one, all that's left to do is multiply.
8x35=280
3x35=105
To be sure we can check our answer by adding them together, 280+105=385.
4 0
1 year ago
What is the scientific notation for this number: .0765 <br> show how you got yoru answer
Daniel [21]
Hey there!!

Scientific notation for 0.0765 is

... 7.65 × 10^-2

Hope my answer helps!!
5 0
3 years ago
Read 2 more answers
Show that the relation R consisting of all pairs(x, y)such that x and y are bit strings of length three or more that agree in th
Mice21 [21]

Answer:

See proof below

Step-by-step explanation:

An equivalence relation R satisfies

  • Reflexivity: for all x on the underlying set in which R is defined, (x,x)∈R, or xRx.
  • Symmetry: For all x,y, if xRy then yRx.
  • Transitivity: For all x,y,z, If xRy and yRz then xRz.

Let's check these properties: Let x,y,z be bit strings of length three or more

The first 3 bits of x are, of course, the same 3 bits of x, hence xRx.

If xRy, then then the 1st, 2nd and 3rd bits of x are the 1st, 2nd and 3rd bits of y respectively. Then y agrees with x on its first third bits (by symmetry of equality), hence yRx.

If xRy and yRz, x agrees with y on its first 3 bits and y agrees with z in its first 3 bits. Therefore x agrees with z in its first 3 bits (by transitivity of equality), hence xRz.

5 0
3 years ago
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