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Alexxx [7]
3 years ago
15

An exam has two probability problems, 1 and 2. If 37% of the students solved problem 1 and 12% of the students solved both probl

ems 1 and 2, what percent of the students who solved problem 1 also solved problem 2?
Mathematics
1 answer:
olga55 [171]3 years ago
7 0

Answer:

  about 32%

Step-by-step explanation:

The desired probability is the conditional probability that problem 2 was solved given that problem 1 was solved. That is ...

  P(2|1) = P(1&2)/P(1) = 12%/37% ≈ .324 ≈ 32%

____

You can also think of it like this. If there were 100 students taking the exam, 37 solved the first problem. Of those 37, 12 solved the second one. 12 is about 32% of 37.

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If arc AD = 62° and arc BC = 28°, then what is the measure of angle AED?
nata0808 [166]
Well according to the Inscribed Angle Theorem, the angle inscribed in a circle is equal to one-half of its intercepted arc. We can apply that theorem to this problem as well. So the measure of AED = 1/2( arc AD + arc BC). Plug in the numbers and simplify.
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6 0
3 years ago
Can you help me solve this please :/
alex41 [277]

Answer:

2√3

Step-by-step explanation:

In a special right triangle called the 30-60-90 triangle, the ratios of the side lengths are x-x√3- 2x respectively. This means that the side opposite to the 60 degrees is x√3 and the side opposite to the 30 degrees is x.

Since the side opposite to the 60 degrees is 6, x√3=6

x√3=6

x=6/√3

rationalize the denominator:

6√3/3

simlify

2√3

so the answer is the third one. 2√3

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