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QveST [7]
2 years ago
14

You roll a six-sided die. Find the probability of each of the following scenarios

Mathematics
1 answer:
romanna [79]2 years ago
6 0

Answer:

a) 1/2

b) 5/6

c) 2/3

Step-by-step explanation:

a)

Rolling a number greater than 3 means you can roll a 4, 5, or 6, which contains rolling a 6. So, the probability is (1+1+1)/6=3/6=\boxed{1/2}

b)

Rolling a number less than 5 means you can roll a 1, 2, 3, or 4, but because you could also roll an even number, so you could also roll a 6.

So, the probability is (1+1+1+1+1)/6=\boxed{5/6}

c)

Rolling a 4 or an odd number means you can roll a 1, 3, 5, or 4. So, the probability is (1+1+1+1)/6=4/6=\boxed{2/3}

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What is the solution to the proportion? 9/x=4/12 Answers: A. 13 B. 27 C. 17 D. 3
Oksana_A [137]
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The Arc Electronic Company had an income of 90 million dollars last year. Suppose the mean income of firms in the same industry
jok3333 [9.3K]

Answer:

0.0869

Step-by-step explanation:

The arc electronic company had an income of 90 million dollars last year.

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Using normal distribution,

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From the normal distribution table, 1.36 = 0.4131

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Recall that when Z is positive, Pr(x>a) = 0.5 - Φ(z)

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= 0.0869

8 0
3 years ago
Solve for x please, will give braknliest
kow [346]
Answer: The answer should be 72

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7 0
2 years ago
Solve each equation (quadratic pattern)
dusya [7]

Answer:  x = 2

<u>Step-by-step explanation:</u>

2^{2x}-2^x-12=0\\\\\text{Let u = }2^x\\\\u^2-u-12=0\\(u-4)(u+3)=0\\\\u-4=0\quad and\quad u+3=0\\u=4\qquad and\quad u=-3\\\\\text{Substitute u with }2^x\\2^x=4\qquad and \quad 2^x=-3\\2^x=2^2\quad and\quad \text{not possible}\\\boxed{x=2}

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Answer:  x = 0

<u>Step-by-step explanation:</u>

3^{2x}+3^{x+1}-4=0\\\\3^{2x}+3^x\cdot3^1-4=0\\\\\text{Let u = }3^x\\u^2+3u-4=0\\\\(u+4)(u-1)=0\\\\u+4=0\quad and\quad u-1=0\\u=-4\qquad and\quad u=1\\\\\text{Substitute u with }3^x\\3^x=-4\qquad and\quad 3^x=1\\\text{not possible}\ and\quad 3^x=3^0\\.\qquad \qquad \qquad \qquad \boxed{x=0}

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Answer:  No Solution

<u>Step-by-step explanation:</u>

4^x+6\cdot 2^x+8=0\\\\2\cdot 2^x+6\cdot 2^x+8=0\\\\\text{Let u = }2^x\\2u+6u+8=0\\8u+8=0\\8u=-8\\u=-1\\\\\text{Substitute u with }2^x\\2^x=-1\\\text{not possible}

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Answer:  No Solution

<u>Step-by-step explanation:</u>

<u>9^x=3^x-6\\\\3\cdot 3^x=1\cdot 3^x-6\\\\\text{Let u = }3^x\\\\3u=u-6\\2u=-6\\u=-3\\\\\text{Substitute u with }3^x\\3^x=-3\\\text{not possible}</u>

<u />

6 0
3 years ago
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