All categories

2 years ago

Which number can each term of the equation be multiplied by to eliminate the fractions before solving?

Mathematics

1 answer:

kogti [31]2 years ago

3 0

Answer:

Step-by-step explanation:

The given fraction is

$- \frac{3}{4} m - \frac{1}{2} = 2 + \frac{1}{4}m$

To clear the fraction, we need to multiply through by the LCM of the denominators.The denominators are 4, 2 and an invisible 1.

The LCM of {4,2,1} is 4.

We multiply through by 2 to obtain:

$- \frac{3}{4} m \times 4 - \frac{1}{2} \times 4 = 2 \times 4 + \frac{1}{4} m \times 4$

This simplifies to

$- 3m - 2 = 8 + m$

The fraction is now eliminated. The required number is 4

You might be interested in

Tommy has 5 jars of marble. Each Jar is filled 2/3 with marbles. How many full Jars does tommy have? Make a model and shade in t

ivann1987 [24]

5 / ( 2 / 3 ) = 7.5

7 full jars

6 0

2 years ago

Ralph is leasing a car worth $24,000 for three years. His leasing company says that the car Ralph is leasing will only be worth

atroni [7]

The answer is C.) 33% i believe. Excuse me if i'm wrong!!!!!

3 0

3 years ago

Read 2 more answers

Find the general solution of the differential equation and check the result by differentiation. (Use C for the constant of integ

atroni [7]

Answer: $y=Ce^(^3^t^{^9}^)$

Step-by-step explanation:

Beginning with the first differential equation:

$\frac{dy}{dt} =27t^8y$

This differential equation is denoted as a separable differential equation due to us having the ability to separate the variables. Divide both sides by 'y' to get:

$\frac{1}{y} \frac{dy}{dt} =27t^8$

Multiply both sides by 'dt' to get:

$\frac{1}{y}dy =27t^8dt$

Integrate both sides. Both sides will produce an integration constant, but I will merge them together into a single integration constant on the right side:

$\int\limits {\frac{1}{y} } \, dy=\int\limits {27t^8} \, dt$

$ln(y)=27(\frac{1}{9} t^9)+C$

$ln(y)=3t^9+C$

We want to cancel the natural log in order to isolate our function 'y'. We can do this by using 'e' since it is the inverse of the natural log:

$e^l^n^(^y^)=e^(^3^t^{^9} ^+^C^)$

$y=e^(^3^t^{^9} ^+^C^)$

We can take out the 'C' of the exponential using a rule of exponents. Addition in an exponent can be broken up into a product of their bases:

$y=e^(^3^t^{^9}^)e^C$

The term e^C is just another constant, so with impunity, I can absorb everything into a single constant:

$y=Ce^(^3^t^{^9}^)$

To check the answer by differentiation, you require the chain rule. Differentiating an exponential gives back the exponential, but you must multiply by the derivative of the inside. We get:

$\frac{d}{dx} (y)=\frac{d}{dx}(Ce^(^3^t^{^9}^))$

$\frac{dy}{dx} =(Ce^(^3^t^{^9}^))*\frac{d}{dx}(3t^9)$

$\frac{dy}{dx} =(Ce^(^3^t^{^9}^))*27t^8$

Now check if the derivative equals the right side of the original differential equation:

$(Ce^(^3^t^{^9}^))*27t^8=27t^8*y(t)$

$Ce^(^3^t^{^9}^)*27t^8=27t^8*Ce^(^3^t^{^9}^)$

QED

I unfortunately do not have enough room for your second question. It is the exact same type of differential equation as the one solved above. The only difference is the fractional exponent, which would make the problem slightly more involved. If you ask your second question again on a different problem, I'd be glad to help you solve it.

7 0

2 years ago

What is the answer 4.6n+7.1n+12.8n-1.6n= ?

Alex787 [66]

The answer would be=22.9n

4 0

2 years ago

Can you Help me please

Evgen [1.6K]

Answer:

-1

Step-by-step explanation:

mn = -3 because 3 × -1 = -3

p^2 = 4 because 2^2 = 4

Then 4 + -3 = -1

6 0

2 years ago

Read 2 more answers