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3 years ago

10

a circle has a radius of 7ft. Find the radian measure of the central angle 0 that intyercepts an arc of length 16ft

1 answer:

Iteru [2.4K]3 years ago

8 0

Answer:

2.29 rads

Step-by-step explanation:

The length of the arc of a circle of radius r is given by;

l = rθ ---------------------------(i)

Where;

l = length of the arc

θ = central angle o that intercepts that arc and measured in radians.

From the question:

l = 16ft

r = 7ft

Substitute these values into equation (i) as follows;

16 = 7θ

Make θ subject of the formula

θ = $\frac{16}{7}$

θ = 2.29

Therefore, the radian measure of the central angle is 2.29 rads

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Answer:

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Step-by-step explanation:

Given: Six cards numbered from $1$ to $6$ are placed in an empty bowl. First one card is drawn and then put back into the bowl then a second card is drawn.

To Find: If the cards are drawn at random and if the sum of the numbers on the cards is $8$ , what is the probability that one of the two cards drawn is numbered $5$ .

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Sample space when sum of cards is $8$ is $\{(3,5),(5,3),(6,2),(2,6),(4,4)\}$

Total number of possible cases $=5$

Sample space when one of the cards is $5$ is $\{(5,3),(3,5)\}$

Total number of possible cases $=2$

Let A be the event that sum of cards is $8$

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Let B be the event when one of the two cards is $5$

probability than one of two cards is $5$ when sum of cards is $8$

$p(\frac{\text{B}}{\text{A}})=\frac{\text{total case when one of the number is 5}}{\text{total case when sum is 8}}$

$p(\frac{\text{B}}{\text{A}})=\frac{2}{5}$

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probability that sum of cards $8$ is and one of cards is $5$

$p(\text{A and B}=p(\text{A})\times p(\frac{\text{B}}{\text{A}})$

$p(\text{A and B})=\frac{5}{36}\times\frac{2}{5}$

$p(\text{A and B})=\frac{1}{18}$

if sum of cards is $8$ then probability that one of the cards is $8$ is $\frac{1}{18}$ , option C is correct.

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