Answer:
The cell interior would experience higher than normal Na+ concentrations and lower than normal K+ concentrations.
Explanation:
Na+/K+ ATPase exists in two forms: Its phosphorylated form has a high affinity for K+ and low affinity for Na+. ATP hydrolysis and phosphorylation of the Na+/K+ pump favor the release of Na+ outside the cell and binding of K+ ions from the outside of the cell. Dephosphorylation of the pump increases its affinity for Na+ and reduces that for K+ ions resulting in the release of K+ ions inside the cells and binding to the Na+ from the cells.
The presence of ATP analog would not allow the pump to obtain its phosphorylated form. Therefore, Na+ ions would not be released outside the cells. This would increase the Na+ concentration inside the cell above the normal. Similarly, the pump would not be able to pick the K+ from the outside of the cell resulting in reduced cellular K+ concentration below the normal range.
ATPase is the enzyme which is required to create ATP and is denoted as option B.
<h3>What is ATPase?</h3>
This type of enzyme is found in the mitochondrion and catalyzes the formation of ATP which provides energy to cells.
The ATP which is referred to as adenosine triphosphate is formed from the molecules known as ADP and inorganic phosphate which are present in the body cells. This ensures that the daily energy needs of the body are met.
Read more about ATPase here brainly.com/question/250287
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Answer: i’m sorry but where is the Answers
Explanation:
Answer:
The difference in the given case indicates that the results are reliable but not accurate. Precision is the tendency of an apparatus to provide repeatable quantities, that is, inaccuracies are minor. The application of standard deviation is generally used as a precision error.
Accuracy refers to the part of an apparatus that provides measures whose average is nearer to the accurate value. It is the reproducibility of an apparatus.
