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3 years ago

HELP ME!!!! I WILL GIVE YOU BRAINLIEST IF YOU GIVE ME THE ANSWER TO THIS!!!!

Mathematics

2 answers:

Dima020 [189]3 years ago

7 0

To find the answer to this you have to first look at what the question is asking. It wants to know how adding the horses weight affects the mean & median. To get this answer you would first find the mean and median of the weights of the animals WITHOUT the horse. The mean WITHOUT the horse is the average. Add all your weights up then divide by 8 since you have 8 animals. The weights of all animals without the horse equal to 285. We then divide 285 by 8, which gives us 35.625. To find the median, we just have to find the middle. The median is 17. Now to see how the original mean and median is affected we do the same procedure again, but this time adding the horses weight in. So the original weights of all animals 285 plus the horses weight 900, brings us to a total of 1,185. We then divide that by 9, since we are including the horse into the average. 1,185/9 = 131.66. The mean DRASTICALLY increases. Now we do the same procedure for median except we add the horse in. The mean is 27. Again we notice an increase in both median and mean. Therefore your answer is B. They both increase, but the mean increased more than the median. Hope this helps :)

Sladkaya [172]3 years ago

5 0

The answer is B because the mean is 131.6 and the median is 36, and obviously 131.6 is the greater value. Hope this helps! If I am wrong, someone in the comments please correct me

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A square napkin is folded in half on the diagonal and placed on the diameter of a round plate (see diagram below). If the folded

Crank

Answer:

$A=81(\pi-1)\ in^2$

Step-by-step explanation:

step 1

Find the area of the plate

The area of a circle is given by the formula

$A=\pi r^{2}$

we have

$r=18/2=9\ in$ ---> the radius is half the diameter

substitute

$A=\pi (9)^{2}\\A=81\pi\ in^2$

step 2

Find the area of the square napkin folded (is a half of the area of the square napkin)

we know that

The diagonal of the square is the same that the diameter of the plate

Applying Pythagorean theorem

$D^2=2b^2$

where

b is the length side of the square

we have

$D=18\ in$

substitute

$18^2=2b^2$

solve for b^2

$b^2=162\ in^2$ -----> is the area of the square

Divide by 2

$162/2=81\ in^2$

step 3

Find the area of the space on the plate that is NOT covered by the napkin

we know that

The area of the space on the plate that is NOT covered by the napkin, is equal to subtract the area of the square napkin folded (is a half of the area of the square napkin) from the area of the plate

$A=(81\pi-81)\ in^2$

simplify

$A=81(\pi-1)\ in^2$

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C = 3b+2d is the same as 3b+2d = C

Let's isolate d. To do this, we first need to subtract 3b from both sides

3b+2d = C
3b+2d-3b = C-3b
2d = C-3b

Then divide both sides by 2

2d = C-3b
2d/2 = (C-3b)/2
d = (C-3b)/2

Take note of the parenthesis as they are very important. We want to divide ALL of C-3b over 2. We don't want to just divide -3b over 2.

The answer choices you have aren't 100% clear but I have a feeling your teacher meant to say d = (C-3b)/2 instead of d = C-3b/2 for choice A

If that assumption is correct, then the answer is choice A.

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Answer:

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okay that it have a nice day

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