To find the answer to this you have to first look at what the question is asking. It wants to know how adding the horses weight affects the mean & median. To get this answer you would first find the mean and median of the weights of the animals WITHOUT the horse. The mean WITHOUT the horse is the average. Add all your weights up then divide by 8 since you have 8 animals. The weights of all animals without the horse equal to 285. We then divide 285 by 8, which gives us 35.625. To find the median, we just have to find the middle. The median is 17. Now to see how the original mean and median is affected we do the same procedure again, but this time adding the horses weight in. So the original weights of all animals 285 plus the horses weight 900, brings us to a total of 1,185. We then divide that by 9, since we are including the horse into the average. 1,185/9 = 131.66. The mean DRASTICALLY increases. Now we do the same procedure for median except we add the horse in. The mean is 27. Again we notice an increase in both median and mean. Therefore your answer is B. They both increase, but the mean increased more than the median. Hope this helps :)
The answer is B because the mean is 131.6 and the median is 36, and obviously 131.6 is the greater value. Hope this helps! If I am wrong, someone in the comments please correct me
