Question

Sally spins a fair spinner numbered 1 - 5 and rolls a fair dice.

Answer 1

Answer: Probability of obtaining a multiple of 3 and a factor of 10 is given by

$\frac{1}{10}$

Step-by-step explanation:

Since we have given that

There is a fair spinner numbered 1-5 and a fair dice

Total number of outcomes of fair spinner = 5

Total number of outcomes of a fair dice = 6

Let Event A: Getting a multiple of 3 on a spinner

Event B: Getting a factor of 10 on a fair dice

The possible outcomes of multiple of 3 on a spinner is

$3$

The possible outcomes of factor of 10 on a fair dice are

$1,2,5$

So,

$P(A)=\frac{1}{5}$

and

$P(B)=\frac{3}{6}=\frac{1}{2}$

Since A and B are independent events so,

$P(A\ and\ B)=P(A).P(B)\\\\P(A\ and\ B)=\frac{1}{5}\times \frac{1}{2}\\\\P(A\ and\ B)=\frac{1}{10}$

Hence, Probability of obtaining a multiple of 3 and a factor of 10 is given by

$\frac{1}{10}$