1005milibars of pressure corresponds to 29.68inches of mercury.
Option D.
<h3><u>Explanation:</u></h3>
Mercury has a density of around 13.6gm/cc. Thus the pressure of inches of mercury will have a huge effect on the value. As far as bar is concerned, it's around the normal atmospheric pressure measured at sea level. Its around 1,00,000 pascals. So from converting a pressure at millibars to inches of mercury, we need to divide the value by a factor of 33.864.
So, pressure in milibars =1005milibars.
So, pressure in inches of mercury = 1005/33.864 = 29.68 inches of mercury.
it goes sedimentary rock to metamorphic is heat and pressure
then metamorphic to magma is melting and magma to igneous rock is crystallization
Thats all i got
both sudden slip on a fault
Correct question:
if a nondisjunction occurs at anaphase I of the first meiotic division, what will the proportion of abnormal gametes (for the chromosomes involved in the nondisjunction)?
Answer:
100%
Explanation:
Nondisjunction at meiosis-I means that two homologous chromosomes of at least one homologous pair fail to separate from each other during anaphase-I. This would result in the formation of one cell with one extra chromosome and the other with one less chromosome by the end of meiosis-I. Meiosis-II in these two cells would maintain this chromosome number in the daughter cells. Therefore, out of the total four gametes formed by the end of the meiosis, two would have one extra chromosome and would be denoted as "n+1". The rest of the two gametes would have one less chromosome and would be denoted as "n-1".
