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Andre45 [30]
3 years ago
10

6d^2+33d+27, what is the answer?

Mathematics
1 answer:
m_a_m_a [10]3 years ago
4 0
6d^2+33d+27 \\ \\ GCF = 3 \\ \\ 3( \frac{6d^2}{3} +  \frac{33d}{3} +  \frac{27}{3} ) \\ \\ 3(2d^2 + 11d + 9) \\ \\ 3(2d^2 + 9d + 2d + 9) \\ \\ 3(d(2d + 9) + (2d + 9)) \\ \\ 3(2d + 9)(d + 1) \\ \\

The final result is: 3(2d + 9)(d + 1)
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Dante is selling donuts outside a huge office building every morning. The first week
inysia [295]

Answer:

<h2>$205</h2>

Step-by-step explanation:

45 - 25 = 20

65 - 45 = 20

as you can see the common difference between the 3 consecutive numbers 25 , 45 and 65 is a constant (20)

so ,we are in an arithmetic sequence case with :

  • first term 25
  • common difference r = 20

Let’s label the sequence: Un

then

Un = U1 + (n-1)×r

    = 25 + (n-1)×20

    = 20n + 5

for n = 10 → U10 = 20(10) + 5 = 200 + 5 = 205

5 0
4 years ago
How do i solve this inequality? -2|3m|+3&lt;-51
9966 [12]

Answer:

m >9  or      m < -9

Step-by-step explanation:

-2|3m|+3<-51

Subtract 3 from each side

-2|3m|+3-3<-51-3

-2|3m|<-54

Divide each side by -2, remembering to flip the inequality

-2|3m|/ -2>-54/-2

|3m|> 27

To get rid of the absolute values, we separate into two inequalities, one as written and one negative, remembering to flip the inequality

3m >27  or     3m <-27

Divide by 3 on each side

3m/3 >27/3  or     3m/3 <-27/3

m >9  or      m < -9

4 0
3 years ago
The denominator of a fraction is four more than three times the numerator. If both numerator and denominator are increased by fo
Oksanka [162]

Let the numerator = x. Then,

The fraction is x/(3x+4).

If both the numerator and denominator are increased by 4, the fraction will be (x+4)/(3x+8), which, according to the question is equal to 9/25. So,

(x+4)/(3x+8) = 9/25

25(x+4) = 9(3x+8)

25x + 100 = 27x + 72

2x = 28

x = 14

Thus, the numerator is 14 and the denominator is (3*14 + 4), which is equal to 46. So the fraction is 14/46.

7 0
3 years ago
a big cruise ship dropped anchor off the Caribbean island of antigua. the heavy anchor dropped into the water at a rate of 2.5 m
AysviL [449]

Falling at the rate of 2.5 m/s for 45 seconds, the anchor fell

                                     (2.5 m/s) x (45 s)  =  112.5 meters .

If it wound up only 40 meters underwater, then it must have fallen

                                      (112.5 m  -  40 m)  =  72.5 meters

from its storage position on the big cruise ship, 
before it ever reached the water.

Since it was falling at the rate of  2.5 m/s, it took

                                     (72.5 m) / (2.5 m/s)  =  29 seconds

to get down to the water surface after it started dropping.

6 0
3 years ago
What are the measures of &lt; 1 and &lt; 2. Show your work or explain your answer.
VashaNatasha [74]

Answer:

m<1 = 105°

m<2 = 75°

Step-by-step explanation:

Since lines c and d are parallel to each other, therefore:

m<2 = 75° (corresponding angles are congruent)

m<1 + m<2 = 180° (linear angle pair)

Substitute

m<1 + 75° = 180°

Subtract 75 from both sides

m<1 = 180° - 75°

m<1 = 105°

4 0
3 years ago
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