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Andre45 [30]
3 years ago
10

6d^2+33d+27, what is the answer?

Mathematics
1 answer:
m_a_m_a [10]3 years ago
4 0
6d^2+33d+27 \\ \\ GCF = 3 \\ \\ 3( \frac{6d^2}{3} +  \frac{33d}{3} +  \frac{27}{3} ) \\ \\ 3(2d^2 + 11d + 9) \\ \\ 3(2d^2 + 9d + 2d + 9) \\ \\ 3(d(2d + 9) + (2d + 9)) \\ \\ 3(2d + 9)(d + 1) \\ \\

The final result is: 3(2d + 9)(d + 1)
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Bill has a rectangular garden that is 3 1/2 feet by 4 1/2 feet. A bag of fertilizer covers 5 1/4 square feet. What is the minimu
sveta [45]

Answer:

3

Step-by-step explanation:

3.5*4.5=15.75 ft^2

15.75/5.25=3 bags

8 0
2 years ago
Choose the congruence theorem that you would use to prove the triangles congruent.
Elena L [17]

<u><em>Answer:</em></u>

SAS

<u><em>Explanation:</em></u>

<u>Before solving the problem, let's define each of the given theorems:</u>

<u>1- SSS (side-side-side):</u> This theorem is valid when the three sides of the first triangle are congruent to the corresponding three sides in the second triangle

<u>2- SAS (side-angle-side):</u> This theorem is valid when two sides and the included angle between them in the first triangle are congruent to the corresponding two sides and the included angle between them in the second triangle

<u>3- ASA (angle-side-angle):</u> This theorem is valid when two angles and the included side between them in the first triangle are congruent to the corresponding two angles and the included side between them in the second triangle

<u>4- AAS (angle-angle-side):</u> This theorem is valid when two angles and a side that is not included between them in the first triangle are congruent to the corresponding two angles and a side that is not included between them in the second triangle

<u>Now, let's check the given triangles:</u>

We can note that the two sides and the included angle between them in the first triangle are congruent to the corresponding two sides and the included angle between them in the second triangle

This means that the two triangles are congruent by <u>SAS</u> theorem

Hope this helps :)

5 0
3 years ago
Read 2 more answers
Factor 70q+60. Write your answer as a product with a whole number greater than 1.
faltersainse [42]

Answer:

10(7q + 6)

Step-by-step explanation:

  1. Find the GCF of 70 and 60: 10
  2. Divide each number by 10 (steps shown below)
  3. 70q ÷ 10 = 7q
  4. 60 ÷ 10 = 6
  5. Re-write the expression with 10: 10(7q + 6)

I hope this helps!

7 0
3 years ago
1/3 How many minutes does April jump rope 1 day? 1 week. Please tell the answer for 1 day and 1 week
Pani-rosa [81]

Answer:

1/3

i don't know laughing out loud

7 0
2 years ago
Three lines of crops in a garden form a triangular shape. Strawberries are planted in a 10 ft line and green beans are planted i
Marat540 [252]

Answer:

p = 19.18

Step-by-step explanation:

This question is illustrated using the attachment and will be solved using cosine formula

a^2 = b^2 + c^2 - 2bcCosA

<em>Let the strawberry side be s, the Green beans be b and the pumpkins be p.</em>

<em />

The cosine formula in this case is:

g^2 = s^2 + p^2 - 2spCosG

Where

s = 10

g = 18

The equation becomes

18^2 = 10^2 + p^2 - 2 * 10 * p * Cos\ 68

324 = 100 + p^2 - 20 * p * 0.375

324 = 100 + p^2 - 7.5p

Collect Like Terms

p^2 - 7.5p + 100 - 324 = 0

p^2 - 7.5p - 224 = 0

Using quadratic formula:

p = \frac{-b\±\sqrt{b^2-4ac}}{2a}

Where

a = 1

b = -7.5

c = -224

p = \frac{-(-7.5)\±\sqrt{(-7.5)^2-4*1*-224}}{2*1}

p = \frac{7.5\±\sqrt{56.25+896}}{2}

p = \frac{7.5\±\sqrt{952.25}}{2}

p = \frac{7.5\± 30.86}{2}

p = \frac{7.5 + 30.86}{2} or p = \frac{7.5 - 30.86}{2}

p = \frac{38.36}{2} or p = \frac{-23.36}{2}

p = 19.18 or p = -11.68

But length can not be negative.

So:

p = 19.18

6 0
2 years ago
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