The use of loop in java is to run a block of code for a certain number of times.
I've included my code in the picture below. Best of luck.
Answer:
if(revenue.cents - expenses.cents < 0){
profit.dollars = revenue.dollars - expenses.dollars - 1;
profit.cents = 1 - revenue.cents - expenses.cents;
}
else{
profit.dollars = revenue.dollars - expenses.dollars;
profit.cents = revenue.cents - expenses.cents;
}
Explanation:
We know that profit is given as: revenue - expenses from the question.
From the given expression above;
if(revenue.cents - expenses.cents < 0)
then profit.dollar will be revenue.dollars - expenses.dollars - 1; the 1 is to be carry over to the cent part. And the profit.cent will be 1 - revenue.cents - expenses.cents;
else the profit.dollars and the profit.cent is computed directly without needing to carry over:
profit.dollars = revenue.dollars - expenses.dollars;
profit.cents = revenue.cents - expenses.cents;
Answer: C) copy the merged array back to the original array
Explanation:
After performing merging of two array then, copy the merge array back to its original array. Merging of two array is done by the process of merge sort. Merging of two array is the similar process of concatenate the two array into the single object.
It basically works on the principle of divide and conquer algorithm. It divide the input value into the two half and then, sorted the accordingly. Then after completion of merging the two array it copy into the original array.
1. The current is the same everywhere in the circuit. This means that wherever I try to measure
the current, I will obtain the same reading.
2. Each component has an individual Ohm's law Voltage Drop. This means that I can calculate
the voltage using Ohm's Law if I know the current through the component and the resistance.
3. Kirchoff's Voltage Law Applies. This means that the sum of all the voltage sources is equal to
the sum of all the voltage drops or
VS = V1 + V2 + V3 + . . . + VN
4. The total resistance in the circuit is equal to the sum of the individual resistances.
RT = R1 + R2 + R3 + . . . + RN
5. The sum of the power supplied by the source is equal to the sum of the power dissipated in
the components.
<span>PT = P1 + P2 + P3 + . . . + PN</span>