Solve for x by plugging in y, then plug x back in
The part of the quadratic formula that dictates whether the function is factorable or not is B. b^2 - 4ac. This determines the number of real, imaginary, negative and positive roots.
In the equation <span>2x^2 + 7x + 3,
we use the quadratic formula
x = -b +- sqrt (b2 -4ac) /2a = -7 +- </span><span>sqrt (49 -24) /4
the answers are x1 =-0.5 and x2 = -3.</span>
1) -10x+y=4
Now, you should substitute x in every situation.
* x=-2 <em>=> -10*(-2)+y=4... 20+y=4... <u>y=-16</u></em>
<em />* x=-1 =>-10*(-1)+y=4... 10+y=4... <u>y=-6</u>
<u />*x=0 => -10*0+y=4... <u>y=4</u>
<u />* x=1 => -10*1+y=4... -10+y=4... <u>y=14</u>
<u />* x=2 => -10*2+y=4... -20+y=4... <u>y=24</u>
<u>2)</u> -5x-1=y
For example: x=0
-5*0-1=-1
<u>
</u>
Answer:
you have the table of the 12in the photo
Step-by-step explanation:
