So assuming x and y remain constant, we can make one of the place holders negative and add the equations together to cancel each other out so
we can cancel out the y terms since 5 is close to 10 (x+5y=6) times 2=2x+10y=12 add this to 6x-10y=12 2x+6x+10y-10y=12+12 8x=24 divide both sides by 8 x=3 subsitute into first equation x+5y=6 3+5y=6 5y=3 y=3/5 x=3