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kolbaska11 [484]

2 years ago

5

Find the area of Rectangle 2 if its length is 1.28 x 10^7 m and its width is 8 x 10^3 m. Write the answer in Scientific Notation

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1 answer:

drek231 [11]2 years ago

8 0

Answer:

1.024E11

Step-by-step explanation:

(1.28 x 10^7) x (8 x 10^3) = 102400000000

In scientific notation: 1.024E11

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Monte performs an experiment using 2 identical graduated cylinders, each with a radius of 2 centimeters. The volume of the liqui

elena55 [62]

Volume of a cylinder is h x r^2 x pi

You have the volume and radius of each one, so taking 188.4=(2)^2 x 3.14 x h1, you can solve this equation for the height h1. Likewise, for the other graduated cylinder you take 314=2^2 x 3.14 x h2, and then solve for h2.

To get the difference in heights, just take h2-h1 after solving the equations for h2 and h1

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2 years ago

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Please help me with this

Dennis_Churaev [7]

Prob ( guessing right) = 0.25 . Get 1 point.

Prob( guessing wrong) = 0.75. Lose 0.5 points.

Expected value = 1(0.25) + (-0.5)(0.75)

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2 years ago

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Determine tie value of 48:64

Taya2010 [7]

48:64 =
48/64 which can be reduced:
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4 0

3 years ago

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How do you solve these problems?

Fed [463]

Answer:

Step-by-step explanation:

Hello,

a. The area of region P is the area of the rectangle 1 * e minus the

$\displaystyle \int\limits^0_1 {e^x} \, dx=[e^x]^{1}_{0}=e-1$

So this is e - (e-1) = e - e + 1 = 1

b. The area of region P is the area of the rectangle 1 * e minus P and minus the

$\displaystyle \int\limits^0_1 {e^{-x}} \, dx=[-e^{-x}]^{1}_{0}=-e^{-1}+1$

So this is

$e - 1 - (-e^{-1}+1) = e-1+e^{-1}-1=e+e^{-1}-2$

This is around 1.08616127...

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

8 0

2 years ago

Somebody please help it would mean a lot!!! i’ll make u the brainliest too

kramer

Answer:

3.14

Step-by-step explanation:

pie is 3.14 just multiply by 3.14

8 0

2 years ago