Let x = # of tickets sold in advance
Let y = # of tickets sold the day of
Cost of the tickets & total sales: 6x & 10y = 6828
You also know y = x + 206
Take the equation mentioned above y = x + 206 and sub it in anywhere the variable y is in the other equations so you'll have this:
6x + 10(x+206) = 6828
Now solve for x to get x = 298
To finish the problem, you must now find the number of y tickets sold.
Sub your x value that you found back into the equation y = x + 206 and you'll get y = 504.
So, 298 tickets were sold in advance and 504 tickets were sold the day of
Answer:
At least two of the lateral faces are congruent.
Step-by-step explanation:
Because the words "at least" are used this means that at a minimum 2 of the faces are congruent. Because the base is in the shape of a triangle, this will definitely be true.
hope this helps:)
Answer: 0.79
Step-by-step explanation:
I will suppose that this is not a continuos probability, as the individual probabilites add up to 100%.
If you want to obtain the probability that x ≤ 0, then you need to add the probability for the cases x= 0, x = -1, x = -2 .... etc
This is:
x = 0, p = .16
x = -2, p = .33
x = -3, p = .13
x = -5, p = .17
Then, the probability where x takes a negative value or zero {-5, -3, -2, 0} is:
P = 0.16 + 0.33 + 0.13 + 0.17 = 0.79
Isolate x by adding 8 to both sides.
3 = x/3
Then, multiply by 3 on both sides.
9 = x
To prove that this is right, you can imput 9 into the equation and it equals -5.
The use of sine and cosine could give you the angle measuments of the triangle, along with the use of tangent. Not only could it give you the angle measurements but the lengths of the sides.
