The first term of an arithmetic progression of 4 terms and ratio equal to 4 whose sum is 100 is 19.
<h3>How to calculate arithmetic progression?</h3>
The first term of an arithmetic progression can be calculated using the following expression:
Sn = n/2 [2a + (n − 1)d]
Where;
- a = first term
- Un = sum
- n = no of terms
- d = common ratio
100 = 2 [2a + (4 - 1)4]
100 = 4a + 24
4a = 100 - 24
a = 76/4
a = 19
Therefore, the first term of an arithmetic progression of 4 terms and ratio equal to 4 whose sum is 100 is 19.
Learn more about arithmetic progression at: brainly.com/question/20385181
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AB = 9 cm
BC = 6cm
CD = 7 cm
AE = 6 cm
3BC = AB
3ED = AE
AB = AE
BC ED
⁹/₃ = ⁶/ₓ
3 · 6 = 9 · x
18 = 9x
9 9
2 = x
ED = 2 cm
Yeah it is 13/16 is a real number
Answer:
<em>y = 150</em>
Step-by-step explanation:
<u>Proportions</u>
It's given y is directly proportional to the square of x-1. It can be expressed as:
![y=k(x-1)^2](https://tex.z-dn.net/?f=y%3Dk%28x-1%29%5E2)
Where k is the constant of proportionality. We know y=24 when x=3. Substituting:
![24=k(3-1)^2](https://tex.z-dn.net/?f=24%3Dk%283-1%29%5E2)
![24=k(2)^2=4k](https://tex.z-dn.net/?f=24%3Dk%282%29%5E2%3D4k)
Solving for k:
k = 24/4 = 6
Thus, the equation is:
![y=6(x-1)^2](https://tex.z-dn.net/?f=y%3D6%28x-1%29%5E2)
When x=6:
![y=6(6-1)^2=6(5)^2=6*25](https://tex.z-dn.net/?f=y%3D6%286-1%29%5E2%3D6%285%29%5E2%3D6%2A25)
y = 150