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2 years ago

What is the equivalent expression for 2x-3

Mathematics

2 answers:

jeyben [28]2 years ago

7 0

Answer: The answer is -6

Step-by-step explanation:

I had this on my math quiz (online schooling) and got it right

OLEGan [10]2 years ago

5 0

Answer: 2x-3

Step-by-step explanation:

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The average car manufactured in the United states in 2001 could drive 24.5 miles on 1 car gallon of gas. Explain how to find the

bogdanovich [222]

Answer:

Step-by-step explanation:

The average car manufactured in the United states in 2001 could drive 24.5 miles on 1 car gallon of gas. To find the number of yards the car can travel on gallon of gas, we would convert 24.5 miles.

1 mile = 1760 yards

24.5 miles = 24.5 × 1760

= 43120 yards

Therefore, the car drives 43120 yards on 1 gallon of gas.

7 0

2 years ago

The perimeter of a rectangle is 640 ft. the length is 15 ft more than the width. find the are of the rectangle.

aev [14]

The answer to this question is area=length*width

7 0

3 years ago

Factor the following expression completely: 3x^2+9x+6

ArbitrLikvidat [17]

Answer:

The answer is 3(+1)(+2)

7 0

2 years ago

Read 2 more answers

Please help me I don’t know this

inessss [21]

Answer:

28 degrees

Step-by-step explanation:

68 = 2m + 12

56 = 2m

m = 28 degrees

6 0

2 years ago

The probability of an event - picking teams. About (a) 10 kids are randomly grouped into an A team with five kids and a B team w

LuckyWell [14K]

Answer: The required probability is $\dfrac{4}{9}$

Step-by-step explanation:

Since we have given that

Number of kids = 10

Number of kids in Team A = 5

Number of kids in Team B = 5

There are three kids in the group, Alex and his two best friends Jose and Carl.

So, number of favourable outcome is given by

$2(\dfrac{8!}{3!\times 5!})$

Total number of outcomes is given by

$\dfrac{10!}{5!\times 5!}$

So, the probability that Alex ends up on the same team with at least one of his two best friends is given by

$\dfrac{2(\dfrac{8!}{5!\times 3!)}}{\dfrac{10!}{5!\times 5!}}\\\\=2\times \dfrac{8!}{3!}\times \dfrac{5!}{10!}\\\\=\dfrac{4}{9}$

Hence, the required probability is $\dfrac{4}{9}$

3 0

2 years ago