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4 years ago

I need help solving this whole thing

Mathematics

1 answer:

xz_007 [3.2K]4 years ago

5 0

Use pemdas to answer this question.

Parenthesis
Exponents
Multiply or
Divide (whichever comes first)
Add or
Subtract (whichever comes first)

If that doesnt work then just try your hardest.

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Mike biked 5 miles on Tuesday, 3 miles on Wednesday, and twice as many miles on Saturday as Wednesday.

svetoff [14.1K]

Mike should bike a total of 11 miles on Sunday

4 0

3 years ago

A researcher is interested in estimating the mean weight of a semi tracker truck to determine the potential load capacity. She t

FinnZ [79.3K]

Answer:

(19229.11 ,20770.89)

Step-by-step explanation:

We are given the following information:

Sample size, n = 17

Sample mean = 20,000 pounds

Sample standard deviation = 1,500 pounds

Confidence level = 95%

Significance level = 5% = 0.05

95% Confidence interval:

$\bar{x} \pm t_{critical}\displaystyle\frac{s}{\sqrt{n}}$

Putting the values, we get,

$t_{critical}\text{ at degree of freedom 16 and}~\alpha_{0.05} = \pm 2.119$

$20000 \pm 2.119(\displaystyle\frac{1500}{\sqrt{17}} ) = 20000 \pm 770.89 = (19229.11 ,20770.89)$

4 0

4 years ago

Consider this equation. cos(θ)= -3/10 If θis an angle in quadrant II, what is the value of tan (θ)?

Alja [10]

Answer:

Step-by-step explanation:

Trigonometry ratio:

$\sf Cos \ \theta = \dfrac{Adjacent \ side}{hypotenuse}=\dfrac{-3}{10}$

We need to find the opposite side using Pythagorean theorem.

opposite side² = hypotenuse² - adjacent side²

= 10² - (-3)²

= 100 - 9

= 91

opposite side = √91

$\sf tan \ \theta = \dfrac{opposite \ side}{adjacent \ side}$

$\sf = \dfrac{\sqrt{91}}{3}$

In quadrant II, value of tan $\theta$ is negative.

$\sf tan \ \theta = -\dfrac{\sqrt{91}}{3}$

7 0

2 years ago

A weatherman stated that the average temperature during July in Chattanooga is 80 degrees or less. A sample of 32 Julys is taken

baherus [9]

Answer:

The correct set of hypotheses is

$H_{0}$ : d=80 degrees

$H_{0}$ : d>80 degrees

Step-by-step explanation:

The weatherman claims that the average temperature during July in Chattanooga is 80 degrees or less. To test this claim, following hypotheses need to be taken:

Let d be the the average temperature during July in Chattanooga, then

$H_{0}$ : d=80 degrees

$H_{0}$ : d>80 degrees

7 0

3 years ago

The length of a rectangle is 14 feet. The width is 6 feet.

Alina [70]

C, 40 feet. (14x2)+(6x2)=28+12=40.

8 0

4 years ago