Ask question

Ask question

All categories

musickatia [10]

3 years ago

12

At a school, 102 students play at least one sport. This is 40% of the students at the school. How many students are at the sc

hool?

2 answers:

mrs_skeptik [129]3 years ago

6 0

255 students is the answer to your problem

viktelen [127]3 years ago

5 0

To get from 40% to 100%, divide by 2 and multiply by 5.
I.e. 40/2 = 20
20 x 5 = 100%

Do the exact same for 102
102/2 = 51
51 x 5 = 255 students

You might be interested in

What is the area of the rectangle

NISA [10]

Answer:

E. 54cm ^2

Step-by-step explanation:

when finding the area just multiply length over width .for example 9 is the length times it to the width 6 you get 54 so the area will be 54 cm

4 0

3 years ago

Read 2 more answers

A rubber band ball weighed some amount. Fatima added two rubber bands to the ball, and now the ball weighed 88 grams. Fatima add

earnstyle [38]

Answer:

Step-by-step explanation:

92

8 0

3 years ago

Vicki puts 10 books on a shelf. The 10 books take up 28 cm. What is the mean (average) thickness of her books? Can I have it wor

netineya [11]

Average thickness of book = Total thickness/mo. of books
= 28 cm/ 10
= 2.8 cm
Thus, on average, each book has 2.8 cm thickness.

5 0

3 years ago

Read 2 more answers

(9x+2)(4x^2+35x-9)=0

pychu [463]

$(9x+2)*(4x^2+35x-9)=0$

we can make this...

$9x+2=0$

and

$4x^2+35x-9=0$

then...

$9x+2=0$

$\boxed{x=-\frac{2}{9}}$

$4x^2+35x-9=0$

$x=\frac{-b\pm\sqrt{b^2-4*a*c}}{2*a}$

$x=\frac{-35\pm\sqrt{35^2-4*4*(-9)}}{2*4}$

$x=\frac{-35\pm\sqrt{1369}}{8}$

$x=\frac{-35\pm37}{8}$

$x_1=\frac{-35+37}{8}=\frac{1}{4}$

$x_2=\frac{-35-37}{8}=-9$

$\boxed{\boxed{S=\{\frac{1}{4},-\frac{2}{9},-9\}}}$

I'm sure about my answer, don't matter the order...

4 0

3 years ago

Read 2 more answers

A rectangular storage container with a lid is to have a volume of 2 m3. The length of its base is twice the width. Material for

Scilla [17]

Answer:

Dimensions are 2 m by 1 meter by 1 meter,

Minimum cost is $ 18.

Step-by-step explanation:

Let w be the width ( in meters ) of the container,

Since, the length is twice of the width,

So, length of the container = 2w,

Now, if h be the height of the container,

Volume = length × width × height

2 = 2w × w × h

1 = w² × h

$\implies h=\frac{1}{w^2}$

Since, the area of the base = l × w = 2w × w = 2w²,

Area of the lid = l × w = 2w²,

While the area of the sides = 2hw + 2hl

= 2h( w + l)

$= 2\times \frac{1}{w^2}(w+2w)$

$=\frac{6w}{w^2}$

$=\frac{6}{w}$

Since, Material for the base costs $1 per m². Material for the sides and lid costs $2 per m²,

So, the total cost,

$C(w) = 1\times 2w^2+2\times 2w^2 + 2\times \frac{6}{w}$

$=2w^2+4w^2+\frac{12}{w}$

$=6w^2+\frac{12}{w}$

Differentiating with respect to w,

$C'(w) = 12w -\frac{12}{w^2}$

Again differentiating with respect to w,

$C''(w) = 12 + \frac{24}{w^3}$

For maxima or minima,

C'(w) = 0

$\implies 12w -\frac{12}{w^2}=0$

$\implies 12w^3 - 12=0$

$w^3-1=0\implies w = 1$

For w = 1, C''(w) = positive,

Hence, for width 1 m the cost is minimum,

Therefore, the minimum cost is C(1) = 6(1)²+12 = $ 18,

And, the dimension for which the cost is minimum is,

2 m by 1 meter by 1 meter.

7 0

3 years ago