Answer:
- No, there is no proportional relationship
Step-by-step explanation:
<u>The proportional relationship is:</u>
- y = kx, which is a special form of linear equation, with zero y-intercept
<u>In the given case we have:</u>
This is a linear function but not proportional relationship because it has y-intercept, different than zero
Answer: The family's weekly income is $1500
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Work Shown:
x = weekly income (in dollars)
16% of x = amount spent on food per week
16% of x = 240
(16/100)*x = 240
0.16*x = 240
0.16*x/0.16 = 240/0.16
x = 1500
To use repeated subtraction, you could keep subtracting 3 until you reach 0.
So, we can do
93-3-3-3-3-3-3-3-3-3-3-3-3-3-3-3-3-3-3-3-3-3-3-3-3-3-3-3-3-3-3-3=0
This has 31 -3s,
So 91/3 is 31.
The answer is (f o g)(x) = 2x^2 - 13
In order to find a composite function, you take the first letter (in this case f) and use that equation. You then remove the variable and put in the second letter (g).
f(x) = 2x + 1 ----> Remove variable.
f(x) = 2( ) + 1 ----> Insert g(x)
(f o g)(x) = 2(x^2 - 7) + 1 ----> Distribute
(f o g)(x) = 2x^2 - 14 + 1 ----> Simplify
(f o g)(x) = 2x^2 - 13
Based on the weight and the model that is given, it should be noted that W(t) in radians will be W(t) = 0.9cos(2πt/366) + 8.2.
<h3>
How to calculate the radian.</h3>
From the information, W(t) = a cos(bt) + d. Firstly, calculate the phase shift, b. At t= 0, the dog is at maximum weight, so the cosine function is also at a maximum. The cosine function is not shifted, so b = 1.
Then calculate d. The dog's average weight is 8.2 kg, so the mid-line d = 8.2. W(t) = a cos t + 8.2. Then calculate a, the dog's maximum weight is 9.1 kg. The deviation from the average is 9.1 kg - 8.2 kg = 0.9 kg. W(t) = 0.9cost + 8.2
Lastly, calculate t. The period p = 2π/b = 2π/1 = 2π. The conversion factor is 1 da =2π/365 rad. Therefore, the function with t in radians is W(t) = 0.9cos(2πt/365) + 8.2.
Learn more about radians on:
brainly.com/question/12939121
