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2 years ago

What is the number? three tens and six ones

Mathematics

2 answers:

Afina-wow [57]2 years ago

8 0

Answer:

36? im pretty sure it's 36

Allisa [31]2 years ago

5 0

The answer is 36. Hopefully I was helpful

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Help me please I only have 5 mins left

Ivahew [28]

Answer:

A.5

B.16

C.11

D.3

E.5

Step-by-step explanation:

6 0

2 years ago

Tell whether the ordered pair is a solution of the equation! please help i will mark you brainliest

larisa86 [58]

Answer:

the answer is

yes to 7 and no to 10

Step-by-step explanation:

7. y = 3x---------> 2*3 = 6

10. y = 7x+2--------------> 2*7=14--> 14+2 = 16

16 does not equal 0

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2 years ago

In the rectangular prism above, BF = 20 units, EF = 11 units, and BC = 9 units. If the rectangular prism is divided into two par

Blababa [14]

The right answer for the question that is being asked and shown above is that: "D. a rectangle with a length of 20 units and a width of 11 units." This is the statement that <span>best describes the resulting cross-section of the prism</span>

8 0

3 years ago

Karen has gallons of apple juice and gallons of orange juice in her refrigerator. How many gallons of juice does Karen have alto

3241004551 [841]

E. All of the above
Because there are gallons

7 0

3 years ago

Suppose four students miss an exam. They tell their instructor that they were carpooling to school together on the day of the ex

tia_tia [17]

Answer:

The probability they each indicate the same tire is $\frac{1}{64}=0.02$

Step-by-step explanation:

There will be 4 cases involved as there are 4 tires.

Probability of choosing front left tire is $\frac{1}{4}$ as there are a total of 4 tires and we need to choose 1.

Now, if all the four students chose the front left tire then the probability is the product of individual probabilities.

Therefore, probability that all 4 students chooses front left tire is:

$P(fl)=(\frac{1}{4})^4$

Similarly, the probabilities of choosing the remaining 3 tires by all the students would be:

$P(fr)=(\frac{1}{4})^4$ , $P(rl)=(\frac{1}{4})^4$ , $P(rr)=(\frac{1}{4})^4$

Therefore, the probability that they indicate the same tire is the sum of all these probabilities.

$P(\textrm{same tire by all})=P(fl)+P(fr)+P(rl)+P(rr)\\ P(\textrm{same tire by all})=(\frac{1}{4})^4\times 4\\ P(\textrm{same tire by all})=\frac{4}{4^4}=\frac{1}{4^3}=\frac{1}{64}=0.02$

7 0

3 years ago