Answer:
800 ft above sea level
Step-by-step explanation:
In order to graph the relationship, we will need to write the expression as the equation of a straight line as shown:
d = mt + b
d is the distance covered
t is the time taken
m is the speed
If you are skateboarding at a pace of 30 meters every 5 seconds. your friend is in-line skating at a pace of 9 meters every 2 seconds, this can be written as (5, 30) and (2, 9)
Get the slope of the line:
m = (9-30)/(2-5)
m = -21/-3
m = 7
Substitute m = 7 and the coordinate (2, 9) into the equation y = mt + b
9 = 7(2) + b
9 = 14 + b
b = -5
The required equation to plot will be expressed as y = 7t - 5
Plot the required graph
Learn more here: brainly.com/question/17003809
The two bottom graphs demonstrate translations.
<h3>
Which figures demonstrate a translation?</h3>
We will have a translation only if:
- The size of the figure does not change (like in option 1, which we can discard).
- If the "direction" of the figure does not change, like in option 2, where you can see that there is a reflection.
The images where the figures are only moved a little bit are the ones that demonstrate just a translation, and these are the two lower ones.
If you want to learn more about translations:
brainly.com/question/24850937
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Answer:
- P(t) = 100·2.3^t
- 529 after 2 hours
- 441 per hour, rate of growth at 2 hours
- 5.5 hours to reach 10,000
Step-by-step explanation:
It often works well to write an exponential expression as ...
value = (initial value)×(growth factor)^(t/(growth period))
(a) Here, the growth factor for the bacteria is given as 230/100 = 2.3 in a period of 1 hour. The initial number is 100, so we can write the pupulation function as ...
P(t) = 100·2.3^t
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(b) P(2) = 100·2.3^2 = 529 . . . number after 2 hours
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(c) P'(t) = ln(2.3)P(t) ≈ 83.2909·2.3^t
P'(2) = 83.2909·2.3^2 ≈ 441 . . . bacteria per hour
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(d) We want to find t such that ...
P(t) = 10000
100·2.3^t = 10000 . . . substitute for P(t)
2.3^t = 100 . . . . . . . . divide by 100
t·log(2.3) = log(100)
t = 2/log(2.3) ≈ 5.5 . . . hours until the population reaches 10,000