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mart [117]
3 years ago
11

I need help answering the question

Mathematics
1 answer:
Troyanec [42]3 years ago
3 0

x = 15 + 4y that is what I got out of it

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Set up and solve an equation for the following business situation.
evablogger [386]

Answer:

Step-by-step explanation:

5(x)-600=800

x=280

3 0
3 years ago
PLEASE HELP I DONT UNDERSTAND!!
slega [8]

Answer:

see explanation

Step-by-step explanation:

3x and 144 are adjacent angles on a straight line and sum to 180°

3x + 144 = 180 ( subtract 144 from both sides )

3x = 36 ← value of 3x

divide both sides by 3

x = 12

and

2y - 5 and 95 are vertically opposite angles and are congruent, so

2y - 5 = 95 ← value of 2y - 5

add 5 to both sides

2y = 100 ( divide both sides by 2 )

y = 50

Then

x + y = 12 + 50 = 62

7 0
2 years ago
Read 2 more answers
Why does the multiplicative inverse of a number have the same sign as the number?
denis23 [38]
<span>Look at the definition of multiplicative inverse. If two numbers are multiplicative inverses of each other, then by definition, their product will be equal to 1. And 1 is a positive number. If both numbers being multiplied are positive, then the result is positive. And of both numbers being multiplied are negative, then the result is still positive. But if one number is positive and the other is negative, then the result is negative. So if you want a positive result, then both numbers you're multiplying have to have the same sign. And since we want a result of 1 for multiplicative inverses and since 1 is positive, then the numbers being multiplied have to have the same sign.</span>
7 0
3 years ago
Can someone plsss help :)
OLga [1]
Set equal to eachother
(2x+1) = 79
Subtract 1 from both sides
2x=78
Divide 2 from both sides
2x/2=78/2
X= 39
5 0
4 years ago
Could someone help me rnnn?
GuDViN [60]

Answer:

vertex = (0, -4)

equation of the parabola:  y=3x^2-4

Step-by-step explanation:

Given:

  • y-intercept of parabola: -4
  • parabola passes through points: (-2, 8) and (1, -1)

Vertex form of a parabola:  y=a(x-h)^2+k

(where (h, k) is the vertex and a is some constant)

Substitute point (0, -4) into the equation:

\begin{aligned}\textsf{At}\:(0,-4) \implies a(0-h)^2+k &=-4\\ah^2+k &=-4\end{aligned}

Substitute point (-2, 8) and ah^2+k=-4 into the equation:

\begin{aligned}\textsf{At}\:(-2,8) \implies a(-2-h)^2+k &=8\\a(4+4h+h^2)+k &=8\\4a+4ah+ah^2+k &=8\\\implies 4a+4ah-4&=8\\4a(1+h)&=12\\a(1+h)&=3\end{aligned}

Substitute point (1, -1) and ah^2+k=-4 into the equation:

\begin{aligned}\textsf{At}\:(1.-1) \implies a(1-h)^2+k &=-1\\a(1-2h+h^2)+k &=-1\\a-2ah+ah^2+k &=-1\\\implies a-2ah-4&=-1\\a(1-2h)&=3\end{aligned}

Equate to find h:

\begin{aligned}\implies a(1+h) &=a(1-2h)\\1+h &=1-2h\\3h &=0\\h &=0\end{aligned}

Substitute found value of h into one of the equations to find a:

\begin{aligned}\implies a(1+0) &=3\\a &=3\end{aligned}

Substitute found values of h and a to find k:

\begin{aligned}\implies ah^2+k&=-4\\(3)(0)^2+k &=-4\\k &=-4\end{aligned}

Therefore, the equation of the parabola in vertex form is:

\implies y=3(x-0)^2-4=3x^2-4

So the vertex of the parabola is (0, -4)

5 0
2 years ago
Read 2 more answers
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