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4 years ago

Rearrange the equation so r is the independent variable. 10q - 5r = 30

Mathematics

1 answer:

Murljashka [212]4 years ago

3 0

Answer:

q = 3 + 1/2r

Step-by-step explanation:

10q - 5r = 30

We want to solve for q

Add 5r to each side

10q - 5r+5r = 30+5r

10q = 30+5r

Divide by 10

10q/10 = 30/10 +5r/10

q = 3 + 1/2r

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Answer:

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Step-by-step explanation:

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So, the left hand side = $\frac{\sin^{6} x-\cos^{6}x }{1-\sin^{2}x \cos^{2}x }$

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= $\frac{(\sin^{2}x-\cos^{2} x )[(\sin^{2}x+\cos^{2}x )^{2}-2\sin^{2}x\cos^{2} x+ \sin^{2}x\cos^{2} x ]}{{1-\sin^{2}x \cos^{2}x }}$ {Since we have the formula $a^{2}+b^{2} = (a+b)^{2} -2ab$ }