Question

1. Find four consecutive even integers such that the sum of the first and third is 6 less than the largest

Answer 1

1. Let the first integer be represented by: 2k

the second integer by: 2(k+1)

the third integer by: 2(k+2)

and the fourth by: 2(k+3)

Then, 2k + 2(k+2) = 2(k+3) - 6

2k + 2k + 4 = 2k + 6 - 6

4k + 4 = 2k

4 = -2k

-2 = k

Answer: -4, -2, 0, 2

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2. Let the first integer be represented by: 2k+1

the second integer by: 2k+3

the third integer by: 2k+5

and the fourth by: 2k+7

Then, 2k+7 = (2k+1) + (2k+3) + (2k+5) + 2

2k + 7 = 6k + 11

-4 = 4k

-1 = k

Answer: -1, 1, 3, 5