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3 years ago

________ is a mathematical sentence written with a greater than

Mathematics

1 answer:

xeze [42]3 years ago

7 0

Answer: An inequality

Step-by-step explanation:

An inequality is a mathematical sentence written with a greater than

sign, or less than sign, or equal to sign or not equal to sign or more than two of these signs at the same time to join two expressions.

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Simplify y^-2/y^-7. Write your answer with a positive exponent only.

attashe74 [19]

Answer:

y^5

Step-by-step explanation:

y^-2/y^-7

When we divide exponents with the same base, we subtract the exponents

y^ ( -2 - -7)

y^ ( -2+7)

y^ 5

4 0

3 years ago

Read 2 more answers

Plz explain and I'll give brainly!!!

miss Akunina [59]

Answer:

(2,21)

Step-by-step explanation:

y = 10.5x

plug 2 for x in the equation

y = 10.5(2)

then multiply 2 by 10.5

y=21

7 0

2 years ago

Let f(x) = 1/x^2 (a) Use the definition of the derivatve to find f'(x). (b) Find the equation of the tangent line at x=2

Verdich [7]

Answer:

(a) $f'(x)=-\frac{2}{x^3}$

(b) $y=-0.25x+0.75$

Step-by-step explanation:

The given function is

$f(x)=\frac{1}{x^2}$ .... (1)

According to the first principle of the derivative,

$f'(x)=lim_{h\rightarrow 0}\frac{f(x+h)-f(x)}{h}$

$f'(x)=lim_{h\rightarrow 0}\frac{\frac{1}{(x+h)^2}-\frac{1}{x^2}}{h}$

$f'(x)=lim_{h\rightarrow 0}\frac{\frac{x^2-(x+h)^2}{x^2(x+h)^2}}{h}$

$f'(x)=lim_{h\rightarrow 0}\frac{x^2-x^2-2xh-h^2}{hx^2(x+h)^2}$

$f'(x)=lim_{h\rightarrow 0}\frac{-2xh-h^2}{hx^2(x+h)^2}$

$f'(x)=lim_{h\rightarrow 0}\frac{-h(2x+h)}{hx^2(x+h)^2}$

Cancel out common factors.

$f'(x)=lim_{h\rightarrow 0}\frac{-(2x+h)}{x^2(x+h)^2}$

By applying limit, we get

$f'(x)=\frac{-(2x+0)}{x^2(x+0)^2}$

$f'(x)=\frac{-2x)}{x^4}$

$f'(x)=\frac{-2)}{x^3}$ .... (2)

Therefore $f'(x)=-\frac{2}{x^3}$ .

(b)

Put x=2, to find the y-coordinate of point of tangency.

$f(x)=\frac{1}{2^2}=\frac{1}{4}=0.25$

The coordinates of point of tangency are (2,0.25).

The slope of tangent at x=2 is

$m=(\frac{dy}{dx})_{x=2}=f'(x)_{x=2}$

Substitute x=2 in equation 2.

$f'(2)=\frac{-2}{(2)^3}=\frac{-2}{8}=\frac{-1}{4}=-0.25$

The slope of the tangent line at x=2 is -0.25.

The slope of tangent is -0.25 and the tangent passes through the point (2,0.25).

Using point slope form the equation of tangent is

$y-y_1=m(x-x_1)$

$y-0.25=-0.25(x-2)$

$y-0.25=-0.25x+0.5$

$y=-0.25x+0.5+0.25$

$y=-0.25x+0.75$

Therefore the equation of the tangent line at x=2 is y=-0.25x+0.75.

5 0

3 years ago

10 feet wide by 30 feet long by 1/3 foot deep.what is the volume?

Ket [755]

----------------------------------------------
Formula
----------------------------------------------
Volume = Length x Width x Height

----------------------------------------------
Apply Formula
----------------------------------------------
Volume = 10 x 30 x 1/3 = 100 ft³

----------------------------------------------
Answer: 100 ft³
----------------------------------------------

4 0

2 years ago

Read 2 more answers

Why are whole numbers subset of intergers,but not subset of natrual numbers

Zepler [3.9K]

I think that whole numbers and natural numbers are the same set:- 1, 2, 3, 4 etc

6 0

3 years ago