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PIT_PIT [208]
3 years ago
6

NUMBER 64 Elijah is selling coupon books for a school fund raiser. The coupon books sell for $ 1 1 . The school

gets $ 8 , $ 3 goes to Elijah's homeroom. If Elijah sold  24 coupon books, how much money did he collect? How much went to his homeroom? How much went to the school? What is the mathematical sentence?
Mathematics
1 answer:
Alisiya [41]3 years ago
7 0
Alright.. so the operations would be multiplication and addition.
The reason for this is you're finding the amount the school got --24*8-- and the amount the homeroom got --24*3-- then add those to get the total he got.

Let's use the variable 't' to represent the total he collected.
We know that the school gets 8 for every book and he sold 24, so this can be represented with 8*24.
We also know that the homeroom gets 3 for every book, so 3*24. Both of these added will give you the total amount of money he earned, 't'.
So the sentence can be written as
t=8(24)+3(24).
t=192+72.
t=264.
So, we can see that the total he earned was $264.
If you look back at the equation, we know that the 8*24 represents the amount the school earned, which means that school earned $192.
The same goes with the amount the homeroom earned; we know that this is represented by 3*24, and thus the homeroom earned $72.
And that's it!!! (:
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Answer:  Option 'C' is correct.

Step-by-step explanation:

Since we have given that

\frac{\left(6x^4+15x^3+10x^2+10x+4\right)}{\left(3x^2+2\right)}

Now, we will find the quotient by factoring the numerator:

\mathrm{Use\:the\:rational\:root\:theorem}\\a_0=4,\:\quad a_n=6\\\\\mathrm{The\:dividers\:of\:}a_0:\quad 1,\:2,\:4,\:\quad \\\mathrm{The\:dividers\:of\:}a_n:\quad 1,\:2,\:3,\:6\\\\\mathrm{Therefore,\:check\:the\:following\:rational\:numbers:\quad }\pm \frac{1,\:2,\:4}{1,\:2,\:3,\:6}\\\\-\frac{2}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+2\\\\=\left(x+2\right)\frac{6x^4+15x^3+10x^2+10x+4}{x+2}\\\\=\frac{6x^4+15x^3+10x^2+10x+4}{x+2}=6x^3+3x^2+4x+2\\\\

Now, we will factor it again:

=\left(6x^3+3x^2\right)+\left(4x+2\right)\\\\=2\left(2x+1\right)+3x^2\left(2x+1\right)\\\\=\left(2x+1\right)\left(3x^2+2\right)

At last we get our factorised form :

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