Option 3:
m∠ABC = 66°
Solution:
Given 
and ABH is a transversal line.
m∠FAB = 48° and m∠ECB = 18°
m∠ECB = m∠HCB = 18°
<u>Property of parallel lines:
</u>
<em>If two parallel lines cut by a transversal, then the alternate interior angles are equal.</em>
m∠FAB = m∠BHC
48° = m∠BHC
m∠BHC = 48°
<u>Exterior angle of a triangle theorem:
</u>
<em>An exterior angle of a triangle is equal to the sum of the opposite interior angles.</em>
m∠ABC = m∠BHC + m∠HCB
m∠ABC = 48° + 18°
m∠ABC = 66°
Option 3 is the correct answer.
Answer:
y+7=1/3(x-3) in point slope
y=1/3x-8 in slope intercept form
Step-by-step explanation:
First put 3x+y=5 in slope-intercept form (y=mx+b)
y=-3x+5
Give that the slope is -3 the perpendicular slope would be 1/3
now using the points (3.-7)
y+7=1/3(x-3) in point slope
y=1/3x-8 in slope intercept form
Answer:
Area = 60
Step-by-step explanation:
(h b)/2
h = 10
b = 12
12 x 10 = 120
120/2 = 60
(h = height and b = base)
Answer:
For sure the third one. I think the 1st one too.
Happy learning!
