Answer:
Wild forest fires cause extensive damage to flora and fauna and result in the destruction of man-made property in and around the area of the fire. To maintain the health of the forest and prevent the large wild forest people or man]nagers use prescribe fire or controlled fired when there is no risk of loss of life and resources.
These controlled fires are used by forest officials and fire managers to prevent or keep wildfires at bay. It helps in cleared-off areas by playing the role of a barrier for fire from spreading further.
There is always the risk of flora fauna and the life of wild animals. They can get killed and lose their habitat and the smoke rose from this fire causes for environmental concern too.
Answer:
By lowering the levels of total cholesterol and low density lipoprotein (LDL)
Explanation:
Dietary fibers are classified into two: the soluble fiber and the insoluble fiber. Studies have show that the soluble fiber play a significant role in lowering blood cholesterol, hence reducing the cardiovascular diseases.
Soluble fiber helps to lower blood cholesterol by its ability to bind to the small intestine which further binds to cholesterol most especially the ad cholesterol (low density lipoprotein). Binding of Fibers to cholesterol prevents them from migrating to the blood stream and to other parts of the body. Since cholesterol can't get into the bloodstream, it exits the body through feces. Fiber has more effect on lowering LDL (bad cholesterol) than High density lipoprotein (good cholesterol.
I think your answer should be B. an organism. Hope this helps. =^-^=
Answer:
Frequency of CW allele in the population= 0.41
Explanation:
A diploid organism has two alleles for each gene. So, a population of 100 plants will have total 100 x 2 = 200 alleles.
The each of the white colored plants have two copies of CW alleles and each pink flowered plant have only one CW allele.
Frequency of CW allele in the population = total number of white flowered plants x 2 + total number of pink colored plants / total population size x 2.
Frequency of CW allele in the population= 22 x 2 + 38 / 100 x 2 = 82 /200 = 0.41
