In normal situations:
-The thin ascending limb is of the loop of henle is impermeable to water. But, is permeable to ions (sodium, chloride) that cross by diffusion.
-Urine osmolality should be 300-900 mOsm/kg of water.
In this case, if the <span>ascending limb of the loop of henle is permeable to water is the same as saying the loop isn't doing it's job of </span>creating a concentration gradient.
Because of that, The process of reabsorption of water and creation of a concentrated urine is not correctly happening.
The answer is E<span>. minimum 300 / maximum 300
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The loop of Henle receives isotonic (300 mOsm/L) fluid, from the <span>proximal convoluted tubule, and since it's not working th way it should it won't change those values. </span>
A- Georgie should have use more than two people per group.
Answer:
1. B.
2. B.
3. A.
Explanation:
1. So, the mother does not but the father does carry the gene for polydactyly. Which means that, the offspring was born Pp and, the dominant trait (P) was exposed.
2. A heterozygous trait is one that has both allele forms (in this case, d and D. If both of the parents are Dd, the offspring will also be Dd, and therefore, he has 1/2 chance of being born deaf.
3. Both you and your spouse will be heterozygous (Ee), therefore, since unattached earlobes are dominant
3.1 When two heterozygous traits are bred, you will get the following combinations: yy, Yy, Yy and YY. Which means that your offspring had a 1/4 chance of having attached earlobes, and that is what happened.
3.2 The third option is incorrect, because when you breed 2 homozygous recessive (ee) traits, all of your offspring will be homozygous recessive (ee), which means that the parents would have to be homozygous recessive, but, they cannot since the dominant trait has applied to them.
Answer to this is copper wire
