This is a polynomial with more than 2 as a degree. Using Descartes Rule of Signs:
f(x) = x⁶ + x⁵ + x⁴ + 4x³ − 12x² + 12
Signs: + + + + − + 2 sign changes ----> 2 or 0 positive roots
f(−x) = (−x)⁶ + (−x)⁵ + (−x)⁴ + 4(−x)³ − 12(−x)² + 12 f(−x) = x⁶ − x⁵ + x⁴ − 4x³ − 12x² + 12
Signs: + − + − − + 4 sign changes ----> 4 or 2 or 0 negative roots
Complex roots = 0, 2, 4, or 6
Answer:
yes
Step-by-step explanation:
Given
57 < 11x ← substitute x = 8
57 ← 88 ← True
Thus x = 8 is a solution to the inequality
Answer:
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Step-by-step explanation:
