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KatRina [158]
3 years ago
8

Can someone show me a equation and answer for this problem Please!?

Mathematics
1 answer:
juin [17]3 years ago
3 0
The equation for this would be 3.50h + 35 = 125

To solve first you need to subtract 35 from both sides

3.50h = 90

Then you need to divide both sides by 3.5

h = 25.7

They can buy 25 balloons

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Please help !!!!!!!!!!!!!​
arlik [135]

Answer:

Step-by-step explanation:

7 0
3 years ago
Please help meeeee :,(
Crank

Answer:

I pretty sure the answer is <u>A</u><u>S</u><u>A</u>, I hope it's right!

6 0
3 years ago
How many eighths are there in six and three quarters
Alex787 [66]
That questions has to do with equivalent fractions, express a fraction in eights.
six and three quarters
= 6 3/4
<span>= 6 + 3/4
</span>= 24/4 + 3/4
= 27/4
and to convert that fraction to eights, just multiply numerator and denominator by 2:
= (27*2)/(4*2)
= 54/8
there are 54 eights in six and three quarters
3 0
4 years ago
If sinA+cosecA=3 find the value of sin2A+cosec2A​
Irina18 [472]

Answer:

\sin 2A + \csc 2A = 2.122

Step-by-step explanation:

Let f(A) = \sin A + \csc A, we proceed to transform the expression into an equivalent form of sines and cosines by means of the following trigonometrical identity:

\csc A = \frac{1}{\sin A} (1)

\sin^{2}A +\cos^{2}A = 1 (2)

Now we perform the operations: f(A) = 3

\sin A + \csc A = 3

\sin A + \frac{1}{\sin A} = 3

\sin ^{2}A + 1 = 3\cdot \sin A

\sin^{2}A -3\cdot \sin A +1 = 0 (3)

By the quadratic formula, we find the following solutions:

\sin A_{1} \approx 2.618 and \sin A_{2} \approx 0.382

Since sine is a bounded function between -1 and 1, the only solution that is mathematically reasonable is:

\sin A \approx 0.382

By means of inverse trigonometrical function, we get the value associate of the function in sexagesimal degrees:

A \approx 22.457^{\circ}

Then, the values of the cosine associated with that angle is:

\cos A \approx 0.924

Now, we have that f(A) = \sin 2A +\csc2A, we proceed to transform the expression into an equivalent form with sines and cosines. The following trignometrical identities are used:

\sin 2A = 2\cdot \sin A\cdot \cos A (4)

\csc 2A = \frac{1}{\sin 2A} (5)

f(A) = \sin 2A + \csc 2A

f(A) = \sin 2A +  \frac{1}{\sin 2A}

f(A) = \frac{\sin^{2} 2A+1}{\sin 2A}

f(A) = \frac{4\cdot \sin^{2}A\cdot \cos^{2}A+1}{2\cdot \sin A \cdot \cos A}

If we know that \sin A \approx 0.382 and \cos A \approx 0.924, then the value of the function is:

f(A) = \frac{4\cdot (0.382)^{2}\cdot (0.924)^{2}+1}{2\cdot (0.382)\cdot (0.924)}

f(A) = 2.122

8 0
3 years ago
Which set of equations is enough information to prove that lines a and b are parallel lines cut by transversal f? m∠4 = 110° and
atroni [7]

see the attached figure to better understand the problem

we know that

If a and b are parallel lines

then

m∠1=m∠4 --------> by alternate exterior angles

m∠3+m∠4=180\° --------> by supplementary angles

so

m∠3+m∠1=180\°

therefore

<u>the answer is the option</u>

m∠1 = 110° and m∠3 = 70°



4 0
3 years ago
Read 2 more answers
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