Answer:
111°
Step-by-step explanation:
Let the centre of the circle be C
mRQ=157 (marked)
The angle at the centre of a circle standing on an arc is twice any angle at the circumference, standing on the same arc. So <SCR=2(SQR)=2(46)=92. mSR=<SCR=92
All the arc measure add up to 360 so:
mSQ+mRQ+mSR=360
mSQ+157+92=360
mSQ=360-249=111
-5,0 and-200 cannot represent the area of polygon
As 0 has no value and there are impossible to make a polygon with negative value
Answer:
Step-by-step explanation:
We want to determine a 90% confidence interval for the true population mean textbook weight.
Number of sample, n = 22
Mean, u = 64 ounces
Standard deviation, s = 5.1 ounces
For a confidence level of 90%, the corresponding z value is 1.645. This is determined from the normal distribution table.
We will apply the formula
Confidence interval
= mean ± z ×standard deviation/√n
It becomes
64 ± 1.645 × 5.1/√22
= 64 ± 1.645 × 1.087
= 64 ± 1.788
The lower end of the confidence interval is 64 - 1.788 = 62.21 ounces
The upper end of the confidence interval is 64 + 1.788 = 65.79 ounces
Therefore, with 90% confidence interval, the true population mean textbook weight is between 62.21 ounces and 65.79 ounces
Answer:
Add all of them together. 1/5 + 2/4 + 4/3 + 3/2 = 53/15 miles
Step-by-step explanation:
1/5 + 2(1/4) + 4(1/3) + 3(1/2)
Answer:
F(10) = P(x = 10) = 0.3
F(5) = P(x = 5) = 0.4
F(1) = P(x = 1) = 0.3
Step-by-step explanation:
Given the following :
Probability estimates given:
Very successful = 0.3
Moderately successful = 0.4
Unsuccessful = 0.3
Yearly revenue (X) :
Very successful = $10 million
Moderately successful = $5 million
Unsuccessful = $1 million
The probability mass function of X:
f(x) = probability of each valie of x
When x = 10:
F(10) = P(x = 10) = 0.3
When x = 5:
F(5) = P(x = 5) = 0.4
When x = 1:
F(1) = P(x = 1) = 0.3
