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rusak2 [61]
3 years ago
12

Two hot air balloons are traveling along the same path away from a town beginning from different locations at the same time. Hen

ry's balloon begins traveling 10 miles from the town and is 24 miles from the town after 2 hours the distance of Tasha's balloon from the town is represented by the function y=6X + 15 which balloon was farther from the town at the beginning and which travel more quickly?
A Tasha's balloon was further from the town at the beginning but Henry's balloon travel more quickly.

B Henry's balloon was farther from the town at the beginning but Tasha's balloon travel more quickly.

C Tasha the balloon was farther from the town of the beginning and it traveled more quickly.

D Henry's balloon was farther from town of the beginning at 8 travel more quickly.
Mathematics
1 answer:
hichkok12 [17]3 years ago
5 0
The answer would be B i think
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Write the point-slope form of the line that passes through (5, 5) and is PARALLEL to a line with a slope of 1/4. Include all of
lesya692 [45]
Parallel lines will have the same slope

y - y1 = m(x - 1)
slope(m) = 1/4
(5,5)...x1 = 5 and y1 = 5
now we sub
y - 5 = 1/4(x - 5) <==== ur parallel line
==================
perpendiculr lines will have a negative reciprocal slope. To find the negative reciprocal, u flip the number and change the sign. So the negative reciprocal of 1/4 is -4....see how I flipped 1/4 and made it 4/1...then changed the sign making it -4/1 or just -4. That will be ur slope of the perpendicular line.

y - y1 = m(x - x1)
slope(m) = -4
(5,5)...x1 = 5 and y1 = 5
now we sub
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marshall27 [118]

Answer: The minimum value of C is 46.

Step-by-step explanation:

Since, Here, We have to find out Min C = 7x+8y

Given the constraints are 2x+y\geq 8 -------(1)

x+y \geq 6   ------------- (2)

x \geq 0, y \geq 0  -------- (3)

Since, For equation 1) x-intercept, (4, 0) and y-intercept (0,8)

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Therefore the area of line 1) does not contain the origin.

For equation 2) x-intercept, (6, 0) and y-intercept (0,6)

And, 0+0\geq 6⇒0\geq 6 ( false)

Therefore the area of line 2) does not contain the origin.

Thus after plotting the constraints 1) 2) and 3) we get Open Shaded feasible region AEB ( Shown in below graph)

At A≡(0,8) , C= 64

At E≡(2,4),  C= 46

At B≡(6,0),  C= 42

Thus at B, C is minimum, And its minimum value = 42


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How do i turn 7/3 in to a whole #
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