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3 years ago

What is an acquisition fee?

1 answer:

8 0

A lessor charges an acquisition fee to cover any expenses they incur while arranging a lease. Acquisition fees can sometimes also refer to charges and commissions that someone pays for the acquisition or purchase of property

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You and your friend each collect rocks and fessis your friend collects three times as many roots and half as many fossils as you

n200080 [17]

Answer:

Number of rocks and fossils collected by you is 1 and 24 respectively

Number of rocks and fossils collected by your friend is 3 and 12 respectively

Step-by-step explanation:

Let the number of Rocks you collect be x

Let the number of Fossils you collect be y

Then the total number pf objects you collected will be

x + y = 25

x = 25 - y------------------------------(1)

Your friend collects three times as many rocks and half as many fossils as you.

This can be written as

3x + y (1/2) = 15

3x + (y/2) = 15-------------------(2)

Substituting (1) in (2)

3(25 - y) + (y/2) = 15

75 - 3y + (y/2) = 15

Grouping the like terms we get,

75 - 15 = 3y = (y/2)

60 = ( 6y - y /2)

60 x 2 = 6y -y

120 = 5y

y = 120/5

y = 24

Substituting y value in equation(1) we get

x = 25 - 24

x= 1

y= 24

Friends collects 3 times rock

so collects 3x =3(1) = 3rocks

Also he collects half as many fossils

That is

y/2 = 24/2 = 12 fossils

Hope this help you! :)

5 0

3 years ago

120/210 *60 (give the answer in hour and minutes)

Katyanochek1 [597]

120/210 = 0.57
0.57 x 60 = 34.2

34 hours and 12 minutes

8 0

3 years ago

A species of beetles grows 32% every year. Suppose 100 beetles are released into a field. How many beetles will there be in 10 y

siniylev [52]

Given that a species of beetles grows 32% every year.

So growth rate is given by

r=32%= 0.32

Given that 100 beetles are released into a field.

So that means initial number of beetles P=100

Now we have to find about how many beetles will there be in 10 years.

To find that we need to setup growth formula which is given by

$A=P(1+r)^n$ where A is number of beetles at any year n.

Plug the given values into above formula we get:

$A=100(1+0.32)^n$

$A=100(1.32)^n$

now plug n=10 years

$A=100(1.32)^{10}=100(16.0597696605)=1605.97696605$

Hence answer is approx 1606 beetles will be there after 20 years.

Now we have to find about how many beetles will there be in 20 years.

To find that we plug n=20 years

$A=100(1.32)^{20}=100(257.916201549)=25791.6201549$

Hence answer is approx 25791 beetles will be there after 20 years.

Now we have to find time for 100000 beetles so plug A=100000

$A=100(1.32)^n$

$100000=100(1.32)^n$

$1000=(1.32)^n$

$log(1000)=n*log(1.32)$

$\frac{\log\left(10000\right)}{\log\left(1.32\right)}=n$

33.174666862=n

Hence answer is approx 33 years.

4 0

3 years ago

Read 2 more answers

Write a quadratic equation to represent the situation. Solve the equation by factoring. Use the table and graphing method to che

Step2247 [10]

Answer:

Step-by-step explanation:

6 0

3 years ago

What is the following sum in simplest form sqrt8+3sqrt2+sqrt32 please HURRY

iragen [17]

Answer:

9sqrt2.

Step-by-step explanation:

sqrt8 + 3sqrt2 + sqrt32

= sqrt4 * sqrt2 + 3 sqrt2 + sqrt16 * sqrt2

= 2sqrt2 + 3sqrt2 + 4 sqrt2

= 9 sqrt2.

3 0

3 years ago

Read 2 more answers