Answer:
Point form: (1,-2)
Equation form: x=1 y= -2
Step-by-step explanation:
Hope it helps
B the set of input values for the function.
Answer:
40320 different ways
Step-by-step explanation:
That problem is a permutation one
We have eight people to occupy one position in a team, without any constraint at all
So
Total number of events = P(8)
P (8) = 8!
P (8) = 8*7*6*5*4*3*2*1
P (8) = 40320 different ways
Complete question :
The GPAs of all students enrolled at a large university have an approximately normal distribution with a mean of 3.02 and a standard deviation of .29.Find the probability that the mean GPA of a random sample of 20 students selected from this university is 3.10 or higher.
Answer:
0.10868
Step-by-step explanation:
Given that :
Mean (m) = 3.02
Standard deviation (s) = 0.29
Sample size (n) = 20
Probability of 3.10 GPA or higher
P(x ≥ 3.10)
Applying the relation to obtain the standardized score (Z) :
Z = (x - m) / s /√n
Z = (3.10 - 3.02) / 0.29 / √20
Z = 0.08 / 0.0648459
Z = 1.2336940
p(Z ≥ 1.2336) = 0.10868 ( Z probability calculator)
Answer:
it is c. x + y = −6
Step-by-step explanation:
i took the test
