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Serjik [45]
3 years ago
12

Use the Intermediate Value Theorem to show that there is a root of the given equation in the specified interval.

Mathematics
1 answer:
Olin [163]3 years ago
5 0

Answer:

The correct option is  d

f(1) =  -5

f(2) =  11

The correct option is d

The correct option is  c

the correct option is  b

Step-by-step explanation:

The given equation is

     f(x) =  x^4 + x -7 =0

The give interval  is (1,2)

 

   Now differentiating the equation

        f'(x) =  4x^3 +7 > 0

Therefore the equation is  positive  at the given interval

       Now at x= 1

  f(1) =  (1)^4 + 1 -7 =-5

       Now at x= 2

  f(2) =  (2)^4 + 2 -7 =11

Now at  the interval (1,2)

      f(1) < 0 < f(2)

i.e

      -5 < 0 < 11

this tell us that there is a value z within 1,2 and

   f(z) =  0

Which implies that there is a root within (1,2) according to the intermediate value theorem

     

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Factorize -pq -pr +mq +mr​
trapecia [35]

Answer:

(q + r) (m - p)

Explanation:

  • -pq - pr + mq + mr​
  • Factor out common term 'p'

= -p(q + r) + mq + mr

  • Factor out common term 'm'

= -p(q + r) + m(q + r)

  • Factor out common term '(q + r)'

= (q + r) (-p + m)

  • (q + r) (m - p)

- PNW

5 0
3 years ago
Solve for x <br><br> Please show your work <br><br> Thank you
Licemer1 [7]
6-4=2
5-X=?
5-2=3
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6 0
3 years ago
Please help will wark brainliest
Dima020 [189]
0.7 divided by 0.35 = 2 is the correct answer :))
3 0
3 years ago
.In the Star Wars franchise, Yoda stands at only 66 centimeters tall. Suppose you want to see whether or not hobbits from the Lo
r-ruslan [8.4K]

Answer:

We conclude that the average height of hobbit is taller than Yoda.

Step-by-step explanation:

We are given that in the Star Wars franchise, Yoda stands at only 66 centimetres tall.

From a sample of 7 hobbits, you find their mean height \bar X = 80 cm with standard deviation s = 10.8 cm.

<u><em /></u>

<u><em>Let </em></u>\mu<u><em> = average height of hobbit.</em></u>

So, Null Hypothesis, H_0 : \mu \leq 66 cm      {means that the average height of hobbit is shorter than or equal to Yoda}

Alternate Hypothesis, H_A : \mu > 66 cm      {means that the average height of hobbit is taller than Yoda}

The test statistics that would be used here <u>One-sample t test statistics</u> as we don't know about population standard deviation;

                     T.S. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n}}}  ~ t_n_-_1

where, \bar X = sample mean height = 80 cm

             s = sample standard deviation = 10.8 cm

             n = sample of hobbits = 7

So, <u><em>test statistics</em></u>  =  \frac{80-66}{\frac{10.8}{\sqrt{7}}}  ~ t_6

                              =  3.429

The value of t test statistics is 3.429.

<em>Now, at 0.01 significance level the t table gives critical value of 3.143 for right-tailed test. Since our test statistics is more than the critical value of t as 3.429 > 3.143, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which </em><em><u>we reject our null hypothesis</u></em><em>.</em>

<em />

Therefore, we conclude that the average height of hobbit is taller than Yoda.

3 0
3 years ago
Correct
Gekata [30.6K]

Answer:

Step-by-step explanation:

                 <u> 4km</u>

\frac{3 }{27}  \frac{miles}{minutes} * \frac{60}{1} \frac{min}{hour} * \frac{1}{.6213}  \frac{km}{mile}

4km ÷ 10.73 km/hr = .37 hr = 22.3 minutes

7 0
3 years ago
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