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3 years ago

Show steps 3y - 4 < or equal to 5

Mathematics

1 answer:

andrey2020 [161]3 years ago

6 0

I showed my steps, and 3y-4 does equal 5

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If discriminant (b^2 -4ac>0) how many real solutions

MaRussiya [10]

Answer:

If Discriminant, $b^{2} -4ac >0$

Then it has Two Real Solutions.

Step-by-step explanation:

To Find:

If discriminant (b^2 -4ac>0) how many real solutions

Solution:

Consider a Quadratic Equation in General Form as

$ax^{2} +bx+c=0$

then,

$b^{2} -4ac$ is called as Discriminant.

So,

If Discriminant, $b^{2} -4ac >0$

Then it has Two Real Solutions.

If Discriminant, $b^{2} -4ac < 0$

Then it has Two Imaginary Solutions.

If Discriminant, $b^{2} -4ac=0$

Then it has Two Equal and Real Solutions.

4 0

3 years ago

Which of the following does this situation repeats

Setler79 [48]

Please attach the question

6 0

3 years ago

How do you find a variable to 4-2(v+9)=26

garik1379 [7]

Answer:

V=20

Step-by-step explanation:

Simplify both sides of the equation.

4−2(v+9)=26

4+(−2)(v)+(−2)(9)=26(Distribute)

4+−2v+−18=26

(−2v)+(4+−18)=26(Combine Like Terms)

−2v+−14=26

−2v−14=26

Step 2: Add 14 to both sides.

−2v−14+14=26+14

−2v=40

Step 3: Divide both sides by -2.

−2v

−2

v=−20

7 0

3 years ago

FiftyFifty adult men in the United States are randomly selected and measured for their body mass index (BMI). Based on that sa

Fynjy0 [20]

Answer: $(23.3,\ 29.7)$

Step-by-step explanation:

The confidence interval for population mean is given by :-

$\overline{x}\pm ME.$ , where $\overline{x}$ is the sample mean and ME is the margin of error .

Given : The sample mean : $\overline{x}=26.5$

Margin of error : $ME=3.2$

Then , the range of values (confidence interval) likely to contain the true value of the population parameter will be :-

$26.5\pm 3.2=(26.5-3.2,\ 26.5+3.2)=(23.3,\ 29.7)$

Hence, the range of values likely to contain the true value of the population parameter = $(23.3,\ 29.7)$

3 0

3 years ago

Read 2 more answers

Can each pencil have a mass of 10.5 grams in a pack of 5 pencils weighing 60 to 95 grams?

kvasek [131]

I don't know if I'm right, but if each pencil is 10.5 grams then you multiply it by 5 ( number of pencils) and you get 52.5, which would not meet the standards of a pack weighing 60 to 95 grams.

8 0

3 years ago