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algol [13]
3 years ago
5

What is the slope of the line that contains (-3, 4) and (7, 5)

Mathematics
1 answer:
Zanzabum3 years ago
4 0
Apply the slope formula as follows:

         5-4            1
m = --------- = ---------
        7-(-3)        10
You might be interested in
Simplify the following:
aivan3 [116]

Answer:

A

Step-by-step explanation:

6 0
3 years ago
Determine if the segment lengths form a triangle. If so, would the triangle be acute, right, or obtuse? 4.1, 8.2, 12.2
goldfiish [28.3K]
Three line segments can form a triangle if the length of the longest segment is greater than the sum of the lengths of the shorter segments.

 4.1 + 8.2 \ \textgreater \  12.2 \\
12.3 \ \textgreater \  12.2 \\
true
They can form a triangle.

Now if c is the length of the longest side and a and b are the lengths of the shorter sides, then:
- if c^2=a^2+b^2, the triangle is right
- if c^2\ \textless \ a^2+b^2, the triangle is acute
- if c^2\ \textgreater \ a^2+b^2, the triangle is obtuse

4.1^2+8.2^2=16.81+67.24=84.05 \\
12.2^2=148.84 \\ \\
148.84\ \textgreater \ 84.05
The triangle is obtuse.

The answer is D.
4 0
2 years ago
Please help! I need this to pass. If you are trying to get points please just chose a different question and don't mess with min
Hunter-Best [27]

Given:

Radius of the cylinder = 2 cm

Height of the cylinder = 3 cm

To find:

The surface area of the cylinder.

Solution:

The surface area of a cylinder is:

A=2\pi rh+2\pi r^2

Where, r is the radius and h is the height of the cylinder.

Putting r=2,h=3,\pi = 3.14, we get

A=2(3.14)(2)(3)+2(3.14)(2)^2

A=37.68+25.12

A=62.8

Therefore, the surface area of the cylinder is 62.8 square cm.

3 0
3 years ago
Let x = 6.
Mars2501 [29]

Put the value of x = 6 to the eqpression 5x² + x - 7:

5(6)² + 6 - 7 = 5(36) + 6 - 7 = 180 + 6 - 7 = 179

<h3>Answer: 179</h3>
5 0
3 years ago
YOOOO NEED HELP ASAP !!! GIVIN BRAINIEST
artcher [175]

Answer:

Correct answer is: f(1) = - 21 ,  f(n) = - 3 · f(n -1)

Step-by-step explanation:

Given geometric sequence:  -21, 63, -189, 567,.........................

Formula for n-th term or a₍ₙ₎ = f(n) = a₁ · q ⁽ⁿ⁻¹⁾  where a₁ is first term and q is quotient (ratio). Formula for (n-1) th term or a₍ₙ₋₁₎ = f(n-1) = a₁ · q ⁽ⁿ⁻²⁾

In this case a₁ = -21 and q = -3

a₍₁₎ = f(1) = -21 · (-3)⁽¹⁻¹⁾ = -21 · (-3)⁰ = -21

f(n) = q¹ · f(n - 1) = q¹ · a₁ q ⁽ⁿ⁻²⁾ = a₁ · q ⁽ⁿ⁻¹⁾ = f(n)

In this case q = -3

f(n) = -3 · f(n -1)

God with you!!!

5 0
3 years ago
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