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tamaranim1 [39]
3 years ago
11

Only number 7 and 8.Any help is appreciated.Thanks!

Mathematics
1 answer:
dmitriy555 [2]3 years ago
3 0
Number seven is d=yd and r=(yd)/2
8 is D=25.08 and r =12.54
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Rona was driving on an asphalt road that had a 35 mile per hour speed limit posted. A lrr r deer jumped out from the side of the
sleet_krkn [62]

Answer:

The answer is "The cops were correct because the average speed would have been about 39.73 miles per hour as per the calculations."

Step-by-step explanation:

Finding the average skid distance:

Average=\frac{70+71+72}{3}=\frac{213}{3}=71

Calculating the skid:  

S=\sqrt{30 \times D \times f\times n}\\\\  

   =\sqrt{30 \times 71 \times 0.78\times 0.95}\\\\=\sqrt{1,578.33}\\\\=39.73

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Factor 3x^3+6x^2+x+2 by grouping
bezimeni [28]
The answer for this question when grouping:

(x+2)(3x^2+1)
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A student earned grades of 84, 78, 84, and 72 out of 100 on her four regular tests. She scored 78% on the final exam and 86% on
adelina 88 [10]

If the student received marks of 84, 78, 84, and 72 on her four normal tests, her weighted mean grade is 81.2 percent.

<h3>What is mean?</h3>

The mean is described as a single number that indicates either the closed value for each item in the collection of data or the mean value for the whole set of data.

On her four regular tests, a student had grades of 84, 78, 84, and 72 out of 100. She received 86 percent on her class projects and 78 percent on the final test.

You may compute the weighted mean as follows:

\rm W_m= 0.4 \times ( \frac{84+78+84+72}{4} )+0.3 \times 78 +0.1 \times 86 + 0.2 \times 87 \\\\ W_m=  81.2 \%

Hence, if the student had marks of 84, 78, 84, and 72 on her four normal tests, her weighted mean grade would be 81.2 percent.

To learn more about the mean refer;

brainly.com/question/22871228

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2 years ago
What is the equation of the line, in general form, that passes through point (-1, -1) and is parallel to the line whose equation
lara31 [8.8K]

ANSWER

x + y + 2 = 0

EXPLANATION

The given line passes through;

(-1,-1) and it is parallel to x + y = 3.

This line given to us can be rewritten as

y=-x+1

It has slope m=-1.

The line parallel to this line also has slope m=-1.

We obtain the equation of the line using the formula:

y-y_1=m(x-x_1)

We substitute the slope and the point to obtain:

y -  - 1 =  - 1(x -  - 1)

y + 1 =  - 1(x + 1)

y =  - x - 1 - 1

The equation of the line is

x + y + 2 = 0

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jolli1 [7]

Answer:

452.16

Step-by-step explanation:

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