Answer:
R V
1 9π in³
2 36π in³
3 81π in³
Step-by-step explanation:
For, r = 1
V = π(1)²9 = 9π in³
For, r = 2
V = π(2)²9 = 4*9π in³ = 36π in³
For r = 3
V = π(3)²9 = 9*9π in³ = 81π in
R V
1 9π in³
2 36π in³
3 81π in³
Answer:
<em>There are 12 boys and 18 girls</em>
Step-by-step explanation:
<u>Equations</u>
There are 30 students in a class. Let's call:
x = number of boys
Since the sum of boys and girls is 30:
30 - x = number of girls
The ratio of boys to girls is 2:3, thus:
![\displaystyle \frac{x}{30-x}=\frac{2}{3}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7Bx%7D%7B30-x%7D%3D%5Cfrac%7B2%7D%7B3%7D)
Crossing denominators:
3x = 2(30 - x)
Operating the parentheses:
3x = 60 - 2x
Adding 2x:
5x = 60
Dividing by 5:
x = 60/5 = 12
x = 12
There are 12 boys and 30-12=18 girls
Ok imma not sure exactly how you would put this in but this is the answer:
Answer:
Step-by-step explanation:
(2005, 12,000) (2005, 12,000)
x1 y1 x2 y2
m= (12,250-1200) / (2010-2005) = 250/5 = 50/1 = or 50