Answer:
Step-by-step explanation:
The altitude to the hypotenuse of a right triangle create two smaller triangles, all of which are similar to the original. This means corresponding sides are proportional.
3. Using the above relationship, ...
short-side/hypotenuse = 8/y = y/(8+23)
y^2 = 8·31
y = 2√62
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long-side/hypotenuse = z/(8+23) = 23/z
z^2 = 23·31
z = √713
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short-side/long-side = 8/x = x/23
x^2 = 8·23
x = 2√46
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4. The picture is fuzzy, but we think the lengths are 25 and 5. If they're something else, use the appropriate numbers. Using the same relations we used for problem 3,
y = √(5·25) = 5√5 . . . . . . . = √(short segment × hypotenuse)
z = √(20·25) = 10√5 . . . . . = √(long segment × hypotenuse)
x = √(5·20) = 10 . . . . . . . . . = √(short segment × long segment)
Answer:
Step-by-step explanation:
p(headache) = 0.45
p(headache | taking a vitamin) = 0.15/0.50 = 0.30
The two probabilities <em>are not equal</em>.
It is c because b is an enlarged version of a
Find the area of the CD. (I used P for pi, too lazy @
[email protected])
A=Pr² - Pr²
radius of the small hole in the middle, 0.75cm
radius of the CD, 6cm
A=3.14*6²-3.14*0.75²
A=111.27375cm²
The Approximate area of the CD is 111.27cm²
To solve this problem you must apply the proccedure shown below:
1. You have that:
-The length is 
feet.
- The width is 
feet.
- The height is 
feet.
2. The box has one base. The cost of the base is:
3. It has four sides. The cost of the sides are:
The answer is: The total cost is 
