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Soloha48 [4]
3 years ago
5

If 8(2r-3)-r=3(3r+2) what does r equal

Mathematics
2 answers:
Xelga [282]3 years ago
7 0
You have to get r by itself once you simplify on both sides

ella [17]3 years ago
4 0

8(2r-3)-r=3(3r+2) 16r-24-r=9r+6 16r-r-9r=6+24 6r=30 R=30÷6 R=5  

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Jane paid $35 for her meal. If the cost of the meal was $30, what was the tax rate.
uranmaximum [27]

Answer:

15% tax

Step-by-step explanation:

7 0
2 years ago
Use the distributive property to remove the parentheses.<br> 3(6-y)
Burka [1]

Answer:

18-3y.

Step-by-step explanation:

3 x 6 = 18

3 x -1y= -3y.

3 0
2 years ago
Read 2 more answers
Customers arrive at a grocery store at an average of 2.1 per minute. Assume that the number of arrivals in a minute follows the
Black_prince [1.1K]

Answer:

a)  P(2)=0.270

b) P(X>3)=0.605

c)  P=0.410

Step-by-step explanation:

We know that customers arrive at a grocery store at an average of 2.1 per minute. We use the  Poisson distribution:

\boxed{P(k)=\frac{\lambda^k \cdot e^{-\lambda}}{k!}}

a)  In this case: \lambda=2.1

P(2)=\frac{2.1^2 \cdot e^{-2.1}}{2}\\\\P(2)=0.270

Therefore, the probability is P(2)=0.270.

b)  In this case: \lambda=2\cdot 2.1=4.2

P(X>3)=1-P(X\leq 3)\\\\P(X>3)=1-\sum_{x=0}^3 \frac{4.2^x \cdot e^{-4.2}}{x!}\\\\P(X>3)=1-0.395\\\\P(X>3)=0.605

Therefore, the probability is P(X>3)=0.605.

c)  We know that two customers came in in the first minute. That is why we calculate the probability of at least 5 customers entering the other 2 minutes.

In this case: \lambda=2\cdot 2.1=4.2

P(X\geq 5)=1-P(X

Therefore, the probability is P=0.410.

4 0
3 years ago
The test to detect the presence of respiratory syncytial virus is 97% accurate for a person who has the virus and 99% accurate f
Setler79 [48]

Answer:

The probability that a randomly selected person gets incorrect result is 2.2 × 10⁻⁴

Step-by-step explanation:

The parameters given are;

The accuracy of the test for a person who has the respiratory synctial virus = 97%

The accuracy of the test for a person who does not have the respiratory synctial virus = 99%

We have;

a = TP =

b = FP

c = FN

d = TN

a/(a + c) = 0.97

d/(d + b) = 0.99

a/(a + b) = 0.97*0.0055/(0.97*0.0055 + (1 - 0.99)*(1-0.0055))

PPV = 0.349 = 34.9%

Therefore, we have;

a/(a + c) = 0.97 and

a/(a + b)  =  0.349

0.97(a + c) =0.349(a + b)

(0.97 - 0.349)a = 0.349·b - 0.97·c

a = (0.349·b - 0.97·c)0.621

b × (1 - 0.0055) = (1 - 0.97)×(1 - 0.0055)

b = 1 - 0.97 = 0.03

Similarly,

c = 1 - 0.99 = 0.01

The proportion of the population that have false positive and false negative = 0.03 + 0.01 = 0.04 = 4%

The probability that a randomly selected person gets incorrect result = 0.04×0.0055 = 0.00022.

5 0
3 years ago
There are 50 campers at day camp and 10 counselors. Write the ratio of campers to counselor as a fraction . Explain how to use e
nadezda [96]
Take the common denominator and divide by 3 then youll get 58
4 0
3 years ago
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