0. 6 0 0
5 3. 0 0 0
− 0
3 0
− 3 0
0 0
− 0
0 0
− 0
0
The length of FG would be BC. This is because FG and BC corresponds on the shape letter sequence. This would mean that EF would be AB, that GH would be CD, and that HE would be DA.
Answer:
The standard form of
is -2 x + 3 y = 21.
Step-by-step explanation:
Here, the given expression is : y= 2/3 x +7
The standard form of the equation is ax + by = c
Now, simplifying the above expression:

or, 
or, -2x + 3y = 21
Hence, the standard form of
is -2x + 3y = 21.
Answer:
3a) The value of x = 56
3b) The measure of ∠ H T M = 90°
3c) The radius of the circle = 53
Step-by-step explanation:
3a) ∵ A F is a tangent to the circle O at point F
∵ Secant AH intersects circle O at point T
∴ (A F)² = (A T)(A H)
∴ 7( x + 7) = (21)² ⇒ ÷ 7
∴ x + 7 = 63
∴ x = 63 - 7 = 56
3b) ∵ HM is a diameter
∴ The measure of the arc HM = 180° ⇒ semi-circle
∵ ∠ H T M is inscribed angle subtended by the arc HM
∴ m ∠ H T M = half the measure of arc HM
∴ m ∠ H T M = 180° ÷ 2 = 90°
3c) ∵ Δ H T M is a right angle triangle at T
∴ (H M)² = (M T)² + (H T)² ⇒ Pythagorean theorem
∴ (H M)² = (90)² + (56)²
∴ (H M)² = 11236
∴ HM =
= 106
∴ OM = 106 ÷ 2 = 53
∵ OM is the radius of the circle O
∴ The radius = 53
Answer:
Plane speed is 60 miles/hour
Wind speed is 20 miles/hour
Step-by-step explanation:
Lets suppose the speed of the plane in still air is s and speed of the wind is w and since speed in the formula below equals speed of the plane plus the wind's speed so speed=s+w for this journey with the wind


For the first journey the trip with the wind:

Here we got our first equation for the second equation we use the information from the second trip which was into the wind. Which means the speed here would be speed=s-w

so now we got our two equations adding both equations would result into the following:

so speed of the plane is 60 miles/hour put the value of s in any our two equations to calculate the wind speed, lets take the first equation:

so the wind speed is 20 miles/hour