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3 years ago

A car moves at a constant speed of 50 miles per hour. How long does it take the car to go 200 miles?

Mathematics

1 answer:

Irina-Kira [14]3 years ago

3 0

Answer: 4 hours

Step-by-step explanation: If you take 50 times 4 it will get you 200. Another way to look at it is the car is going 50 miles per hour, so in one hour the car has gone 50 miles, in two hours it’s gone 100, three hours it’s gone 150, so in four hours it’s gone 200 miles

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Elaine found the following in her pocket. How much money was in her pocket

jenyasd209 [6]

Answer:

we need the numbers... or like the coins, or something to solve it with. you need to include what was actually in here pocket lol

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2 years ago

Solve the following equations. √3 ⋅ 3^3x = 9

GREYUIT [131]

Answer:

The solution is $x = 0.5$

Step-by-step explanation:

We need to write everything as a power of 3.

We know that:

$\sqrt{a} = a^{0.5}$

$\sqrt{3} = 3^{0.5}$

And

$9 = 3^{2}$

This following property is also important:

$\frac{a^{b}}{a^{c}} = a^{b-c}$

To solve, the first step is putting everything with the variable x on one side and everything without the variable x on the other side

$\sqrt{3}.3^{3x} = 9$

$3^{0.5}.3^{3x} = 3^{2}$

$3^{3x} = \frac{3^{2}}{3^{0.5}}$

$3^{3x} = 3^{2-0.5}$

$3^{3x} = 3^{1.5}$

This means that:

$3x = 1.5$

$x = \frac{1.5}{3}$

$x = 0.5$

5 0

3 years ago

Add The Following Polynomials?

Mashcka [7]

(6x^3 + 4x-2) + (4x^2 + 3x^3 - 6)=
6x^3 + 4x-2 + 4x^2 + 3x^3 - 6=
9x^3+4x^2+4x-8

4 0

3 years ago

B) The price of an electric fan is fixed 20% above its cost price. When it is sold allowing

kenny6666 [7]

Answer:

$\boxed{ \boxed{ \sf {Marked \: price \: = Rs \: 1500}}}$

$\boxed{ \bold{ \boxed{ \sf{Selling \: price = \: Rs \: 1230}}}}$

Step-by-step explanation:

Let Cost price ( C.P ) be x

Finding the Marked price and selling price 

Marked price = $\sf{x + 20\% \: of \: x}$

⇒ $\sf{x + \frac{20}{100} \times x}$

⇒ $\sf{ \frac{x \times 100 + 20x}{100} }$

⇒ $\sf{ \frac{120x}{100} }$ ⇒ ( i )

Selling price = $\sf{marked \: price \: - 18\% \: of \: marked \: price}$

⇒ $\sf{ \frac{120x}{100} - \frac{18}{100} \times \frac{120x}{100} }$

⇒ $\sf{ \frac{120x}{100} - \frac{54x}{250} }$

⇒ $\sf{ \frac{120x \times 5 - 54x \times 2}{500} }$

⇒ $\sf{ \frac{600x - 108x}{500} }$

⇒ $\sf{ \frac{492x}{500} }$ ⇒ ( ii )

Finding the value of x ( Cost price )

$\sf{loss = cost \: price - selling \: price}$

⇒ $\sf{20 = x - \frac{492x}{500} }$

⇒ $\sf{20 = \frac{x \times 500 - 492x}{500} }$

⇒ $\sf{20 = \frac{8x}{500} }$

⇒ $\sf{8x = 10000}$

⇒ $\sf{x = \frac{10000}{8} }$

⇒ $\sf{x = \: Rs \: 1250}$

Value of x ( cost price ) = Rs 1250

Now, Replacing the value of x in ( i ) in order to find the value of marked price

$\sf{marked \: price = \frac{120x}{100} }$

⇒ $\sf{ \frac{120 \times 1250}{100} }$

⇒ $\sf{ \: Rs \: 1500}$

Replacing value of x in ( ii ) in order to find the value of selling price

$\sf{selling \: price = \frac{492 \: x}{500} }$

⇒ $\sf{ \frac{615000}{500} }$

⇒ $\sf{ \: Rs \: 1230}$

Thus , Marked price of the fan = Rs 1500

Selling price of the fan = Rs 1230

Hope I helped!

Best regards!!

6 0

3 years ago

2x=160, can you help me with this, and show steps?

Mars2501 [29]

Just divide both sides by 2 because you want to do the opposite operation, to isolate x so if you do you get 80 so x = 80

6 0

3 years ago

Read 2 more answers