Answer:
Below.
Step-by-step explanation:
15y + 12x = 18
5y + 4x = 6
The second equations is the first times 3 so they are basically the same.
Infinite Solutions.
2x+ 3y= 12
-6y= 4x-24 Rearranging the second equation:
-4x - 6y = -24 Multiplying the first equation by 2:
4x + 6y = 24
- we see that the last equation is -1 * previous equation.
So there are infinite solutions.
Answer:
78 m^2 Unless I got some of the measurements wrong, kinda hard to see them.
Step-by-step explanation:
The surface area will be the sum of the area of each face. so lets see, there is the base (in this orientation) which is a 8x3 rectangle it looks like.
then two trianglular sides with both having a base of 8 and height of 3
then two "roof" pieceswhich are rectangles again, one side of 3 and the other 5.
Now we add each face up.
rectangular base = 3x8 = 24
2 triangular sides = 2(.5*8*3) = 24
2 rectangular roof pieces = 2(5*3) = 30
Now add it all up
24+24+30 = 78
Answer:
Step-by-step explanation:
From the given picture,
Given : l₁ and l₂ are the parallel lines and ∠2 ≅ ∠4
To prove: ∠1 ≅ ∠4 and ∠4 ≅ ∠3
Statements Reasons
1). l₁ ║ l₂ and ∠2 ≅ ∠4 1). Given
2). ∠1 ≅ ∠2 2). Vertical angle theorem
3). ∠1 ≅ ∠4 3). Given
4). ∠1 ≅ ∠3 4). Corresponding angle theorem
5). ∠4 ≅ ∠3 5). Transitive property of congruence
Answer:
- Two sided t-test ( d )
- 0.245782 ( c )
- Since P-value is too large we cannot conclude that the students’ weight are different for these two schools. ( c )
- The test is inconclusive; thus we cannot claim that the average weights are different. ( b )
Step-by-step explanation:
1) Test performed is a Two sided test and this because we are trying to determine the mean difference between two groups irrespective of their direction
<u>2) Determine the P-value ( we will use a data-data analysis approach on excel data sheet while assuming Unequal variances )</u>
yes No
Mean 94.47059 89.76471
Variance 173.2647 95.19118
Observations 17 17
df 30
t Stat 1.184211
P(T<=t) one-tail 0.122814
t Critical one-tail 1.697261
P(T<=t) two-tail 0.245782
Hence The p-value = 0.245782
3) Since P-value is too large we cannot conclude that the students’ weight are different for these two schools.
4) The test is inconclusive; thus we cannot claim that the average weights are different.
