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Aleonysh [2.5K]
3 years ago
10

Rolf spent 15 hours last week practicing his saxophone. If 3/10 of the time was spent practicing warm-up routines, how much time

did he spend practicing warm-up routines?
Mathematics
1 answer:
rusak2 [61]3 years ago
5 0

Answer:

(3/10)*15= 9/2= 4.5 hours practicing warm up routines

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The lengths of a trapezoid are represented by 2x + 3 , 4x - 5, 3x + 2, and 5x - 9. What is the perimeter of the trapezoid expres
tester [92]

Answer: 120x4+270

Step-by-step explanatio:

Umm so I’m only in 8th grade and this was on my test so the 4 is an exponent

3 0
3 years ago
The volume of a right circular cone is found using the equation V = 1 3 π r 2 h . Which equation represents the volume solved fo
alex41 [277]

Solving for a variable in an equation means, we are changing the subject of formula of the equation.

The equation of r is: \mathbf{r = \sqrt{\frac{3V}{\pi h}}}

The equation is given as:

\mathbf{V = \frac 13 \pi r^2h}

We start by multiplying both sides by 3

\mathbf{V \times 3= \frac 13 \pi r^2h \times 3}

Rewrite as:

\mathbf{3V= \pi r^2h}

Divide both sides by \mathbf{\pi h}

\mathbf{\frac{3V}{\pi h}= \frac{\pi r^2h}{\pi h}}

Cancel out common factors

\mathbf{\frac{3V}{\pi h}= r^2}

Take square roots of both sides

\mathbf{\sqrt{\frac{3V}{\pi h}}= \sqrt{r^2}}

Evaluate the right-hand sides

\mathbf{\sqrt{\frac{3V}{\pi h}}= r}

Make r the subject

\mathbf{r = \sqrt{\frac{3V}{\pi h}}}

Hence, the resulting equating for r is:

\mathbf{r = \sqrt{\frac{3V}{\pi h}}}

Read more about the subject of formulas at:

brainly.com/question/21866313

6 0
3 years ago
What operation should I use to solve -6×=24
Masja [62]

Answer:

Step-by-step explanation:

-6x=24

+6  +6

x= 30

7 0
2 years ago
55 points see attachment below
Ludmilka [50]

Answer:

  f(3) = -20

Step-by-step explanation:

To find the value of a function, substitute the number for the variable and do the arithmetic.

  f(x) = -2x^2 +x -5 . . . . . . given

  f(3) = -2(3^2) +(3) -5 . . . . function value for x = 3

  f(3) = -2(9) +3 -5 = -18 +3 -5

  f(3) = -20

4 0
2 years ago
Given f(x) = x3 – 2x2 – x + 2, <br><br> the roots of f(x)
anyanavicka [17]

f(x) = x³ – 2x² – x + 2

 

 0 = x3 – 2x2 – x + 2

 (x-2)(x-1)(x+1)=0

 x1=-1

 x2=1

 x3=2

5 0
3 years ago
Read 2 more answers
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