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Marizza181 [45]
3 years ago
11

The table represents a linear equation. A two column table with 5 rows. The first column, x, has the entries, negative 4, negati

ve 2, 6, 10. The second column, y, has the entries, negative 11, negative 6, 14, 24. Which equation correctly uses point (–2, –6) to write the equation of this line in point-slope form? y – 6 = y minus 6 equals StartFraction 5 Over 2 EndFraction left-parenthesis x minus 2 right parenthesis.(x – 2) y – 6 = negative StartFraction 2 Over 5 EndFraction. (x – 2) y + 6 = y plus 6 equals StartFraction 2 Over 5 EndFraction left-parenthesis x plus 2 right parenthesis.(x + 2) y + 6 = y plus 6 equals StartFraction 5 Over 2 EndFraction left-parenthesis x plus 2 right parenthesis.(x + 2)
Mathematics
2 answers:
Brut [27]3 years ago
7 0

Answer:

y+6=5/2(x+2)

Step-by-step explanation:

y + 6 = y plus 6 equals StartFraction 5 Over 2 EndFraction left-parenthesis x plus 2 right parenthesis.(x + 2)

stepan [7]3 years ago
6 0

Answer:

y+6=\frac{5}{2}(x+2)

y plus 6 equals StartFraction 5 Over 2 EndFraction left-parenthesis x plus 2 right parenthesis.

Step-by-step explanation:

we have the ordered pairs

(-4,-11),(-2,-6),(6,14),(10,24)

step 1

Find the slope

The formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}

take the points

(-4,-11),(-2,-6)

substitute the given values

m=\frac{-6+11}{-2+4}

m=\frac{5}{2}

step 2

Find the equation in point slope form

y-y1=m(x-x1)

we have

m=\frac{5}{2}

(x1,y1)=(-2,-6)

substitute in the equation

y-(-6)=\frac{5}{2}(x-(-2))

y+6=\frac{5}{2}(x+2)

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The linear function f i with values f(-1) = 10 and f(5) = -1 is f(x)
zhenek [66]
Answer:

Use the two points to compute the slope, m, then use one of the points in the form <span>y=m<span>(x)</span>+b</span> to find the value of b.

Explanation:

The equation for the slope, m, of a line is:

<span>m=<span><span><span>y1</span>−<span>y0</span></span><span><span>x1</span>−<span>x0</span></span></span> [1]</span>

The equation <span><span>f<span>(2)</span></span>=−1</span> tells us that <span><span>x0</span>=2and<span>y0</span>=−1</span>; substitute this into equation [1]:

<span>m=<span><span><span>y1</span>−−1</span><span><span>x1</span>−2</span></span> [2]</span>

The equation <span><span>f<span>(5)</span></span>=4</span> tells us that <span><span>x1</span>=5and<span>y1</span>=4</span>; substitute this into equation [2]:

<span>m=<span><span>4−−1</span><span>5−2</span></span> [3]</span>

<span>m=<span>53</span></span>

Substitute <span>53</span> for m into the equation <span>y=m<span>(x)</span>+b</span>

<span>y=<span>53</span>x+b [4]</span>

Substitute 2 for x and -1 for y and the solve for b:

<span>−1=<span>53</span><span>(2)</span>+b</span>

<span>b=−<span>133</span></span>

Substitute <span>−<span>133</span></span> for b in equation [4]:

<span>y=<span>53</span>x−<span>133</span> [5]</span>

Check:

<span>−1=<span>53</span><span>(2)</span>−<span>133</span></span>
<span>4=<span>53</span><span>(5)</span>−<span>133</span></span>

<span>−1=−1</span>
<span>4=<span>4</span></span>

<span><span>
</span></span>

<span><span>Hope this helps </span></span>

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Michael has a set of 24 math problems to do for homework. Michael completed 1/4 of his homework in 3/4 of an hour. If he continu
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Given:

Total number of problems = 24

Michael completed \dfrac{1}{4} of his homework in \dfrac{3}{4} of an hour.

To find:

What fraction of his homework would he complete in one hour.

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We have,

Part of work done in \dfrac{3}{4} of an hour =\dfrac{1}{4}

Part of work done in an hour =\dfrac{4}{3}\times \dfrac{1}{4}

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Therefore, he complete \dfrac{1}{3} of his homework in 1 hour. Hence, all options are incorrect.

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