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Elza [17]
2 years ago
6

The hypotenuse of a right triangle is 6 inches. if one of the legs is 2 inches, find the degree measure of each angle

Mathematics
1 answer:
miskamm [114]2 years ago
5 0
A and b are the 2 smaller sides, and c = hypotenus; only for right triangles,
Pythagorean Theorem states that:
{c}^{2}  =  {a}^{2}  +  {b}^{2}
given c = 6 in., a = 2 in.
{c}^{2}  =  {a}^{2}  +  {b}^{2}  \\  {6}^{2}  =  {2}^{2}  +  {b}^{2}  \\ {b}^{2} =  {6}^{2}  -  {2}^{2} = 36 - 4   \\ \sqrt{ {b}^{2} }  =  \sqrt{36 - 4}  =  \sqrt{32}
b =  \sqrt{32}   =  \sqrt{16}  \times  \sqrt{2}  = 4 \sqrt{2}  \\ b = 5.66 \: inches
So the three side are 2, 6, and 5.66 inches
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81x^4

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Simplify. Your answer should contain only positive exponents with no fractional exponents in the denominator.
mart [117]

Answer:

\dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{4y^{2}}.

Step-by-step explanation:

The given expression is  

\dfrac{3y^{\frac{1}{4}}}{4x^{-\frac{2}{3}}y^{\frac{3}{2}}\cdot 3y^{\frac{1}{2}}}

We need to simplify the expression such that answer should contain only positive exponents with no fractional exponents in the denominator.

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\dfrac{3}{4\cdot 3}\cdot \dfrac{y^{\frac{1}{4}}}{x^{-\frac{2}{3}}y^{\frac{3}{2}+\frac{1}{2}}}    [\because a^ma^n=a^{m+n}]

\dfrac{1}{4}\cdot \dfrac{y^{\frac{1}{4}}}{x^{-\frac{2}{3}}y^{2}}

\dfrac{1}{4}\cdot \dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{y^{2}}         [\because a^{-n}=\dfrac{1}{a^n}]

\dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{4y^{2}}

We can not simplify further because on further simplification we get negative exponents in numerator or fractional exponents in the denominator.

Therefore, the required expression is \dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{4y^{2}}.

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