Question

Unit 4 midFind the Perimeter of the triangle. Round 2 decimal places.

Answer 1

A (-2, 3) B(3, 0) C(-4,-3)

$\text {Length of AB = } \sqrt{(-2-3)^2+ (3-0)^2}$

$\text {Length of AB = } \sqrt{(-5)^2+ (3)^2}$

$\text {Length of AB = } \sqrt{25 + 9}$

$\text {Length of AB = } \sqrt{34}$

$\text {Length of AB = } 5.83$

$\text {Length of BC = } \sqrt{(3+4)^2+ (0+3)^2}$

$\text {Length of BC = } \sqrt{(7)^2+ (3)^2}$

$\text {Length of BC = } \sqrt{49 + 9}$

$\text {Length of BC = } \sqrt{58}$

$\text {Length of BC = } 7.62$

$\text {Length of AC = } \sqrt{(-2+4)^2+ (3+3)^2}$

$\text {Length of AC = } \sqrt{(2)^2+ (6)^2}$

$\text {Length of AC = } \sqrt{4 + 12}$

$\text {Length of AC = } \sqrt{16}$

$\text {Length of AC = } 4}$

Perimeter = 5.83 +  7.62 + 4 = 17.45 units