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MrRissso [65]
3 years ago
5

Find the distance between j(4,-5) and h(3,3)

Mathematics
1 answer:
Savatey [412]3 years ago
8 0
Jh=√((4-3)²+(-5-3)²)
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T-shirts are on sale for 35% off. If a T-shirt originally costs 17.40, what is the sale price?
ch4aika [34]

Answer:

49.7142857143

Step-by-step explanation:

17.40/35%

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3 years ago
What is the algebraic expression for the following word phrase: the quotient of 8 and the sum of 3 and m?
serg [7]

we know that

the algebraic expression is equal to

\frac{8}{(3+m)}

therefore

<u>the answer is</u>

\frac{8}{(3+m)}


5 0
3 years ago
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Perform the indicated computation. Write the answer in scientific notation. 12x10^4\3x10^−2
Paul [167]

Let us consider the given expression:

\frac{12 \times 10^{4}}{3 \times 10^{-2}} in the scientific notation.

= \frac{12 \times 10^{4} \times 10^{2}}{3 }

[Using the law of exponents, which states

a^{m} \times a^{n} = a^{m+n} ]

= \frac{12 \times 10^{6}}{3}

On dividing, we get

= 4 \times 10^{6}

Hence, it is the required scientific notation of the given expression.

6 0
3 years ago
Factorise x^2-6 need help for my hegarty maths
Ganezh [65]

you can't factorize it in rational numbers

5 0
3 years ago
Find the value of x in each case: Given: Iso. ΔABC, HM ∥DG Find: x, m∠CAB, m∠CBA
AleksAgata [21]

1. Start with ΔCIJ.

  • ∠HIC and ∠CIJ are supplementary, then m∠CIJ=180°-7x;
  • the sum of the measures of all interior angles in ΔCIJ is 180°, then m∠CJI=180°-m∠JCI-m∠CIJ=180°-25°-(180°-7x)=7x-25°;
  • ∠CJI and ∠KJA are congruent as vertical angles, then m∠KJA =m∠CJI=7x-25°.

2. Lines HM and DG are parallel, then ∠KJA and ∠JAB are consecutive interior angles, then m∠KJA+m∠JAB=180°. So

m∠JAB=180°-m∠KJA=180°-(7x-25°)=205°-7x.

3. Consider ΔCKL.

  • ∠LFG and ∠CLM are corresponding angles, then m∠LFG=m∠CLM=8x;
  • ∠CLM and ∠CLK are supplementary, then m∠CLM+m∠CLK=180°, m∠CLK=180°-8x;
  • the sum of the measures of all interior angles in ΔCLK is 180°, then m∠CKL=180°-m∠CLK-m∠LCK=180°-(180°-8x)-42°=8x-42°;
  • ∠CKL and ∠JKB are congruent as vertical angles, then m∠JKB =m∠CKL=8x-42°.

4. Lines HM and DG are parallel, then ∠JKB and ∠KBA are consecutive interior angles, then m∠JKB+m∠KBA=180°. So

m∠KBA=180°-m∠JKB=180°-(8x-42°)=222°-8x.

5. ΔABC is isosceles, then angles adjacent to the base are congruent:

m∠KBA=m∠JAB → 222°-8x=205°-7x,

7x-8x=205°-222°,

-x=-17°,

x=17°.

Then m∠CAB=m∠CBA=205°-7x=86°.

Answer: 86°.

3 0
3 years ago
Read 2 more answers
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