I just need to know how to calculate

Mathematics

1 answer:

Anton [14]2 years ago

8 0

Answer:

$-a^{2}$

Step-by-step explanation:

$\frac{-1}{a^{-2} } = \frac{-1}{\frac{1}{a^{2} } } = -1 * \frac{a^{2} }{1} = -a^{2}$

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7. The hexagon GIKMPR is regular. The dashed line segments form 30 degree angles. what is the image of oh after a rotation of 18

velikii [3]

Answer:

The image of OH is ON.

Step-by-step explanation:

Te figure GIKMPR is a regular hexagon. The number of vertices of a regular hexagon is 6. The central angle between any two consecutive vertices is 60 degree.

The dashed line segments form 30 degree angles.

If we rotate the hexagon 180 degree about O, then the each point shifts to 6th place from its original place.

Since we rotate the hexagon 180 degree about O, so the image and preimage lies on a straight line. Because a straight line make angle of 180 degree.

The line OH and ON lies on a straight line therefore the image of OH is ON.

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3 years ago

Which statement best describes how to determine whether f(x) = x3 + 5x + 1 is an even function?

ch4aika [34]

I have my notes here that will help you in answering the problem:

Test to determine if a function y=f(x) is even, odd or neither: Replace x with -x and compare the result to f(x). If f(-x) = f(x), the function is even. If f(-x) = - f(x), the function<span>is odd.
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I hope my answer has come to your help. God bless and have a nice day ahead!

7 0

3 years ago

(5/6)^4x=(36/25)^9-x, please help solve for x, and the 9-x is all superscript

stiks02 [169]

$\frac{36}{25}=\frac{6^2}{5^2}=\left(\frac{6}{5}\right)^2=\left(\frac{5}{6}\right)^{-2}\\\\therefore:\\\\\left(\frac{5}{6}\right)^{4x}=\left[\left(\frac{5}{6}\right)^{-2}\right]^{9-x}\\\\\left(\frac{5}{6}\right)^{4x}=\left(\frac{5}{6}\right)^{-2(9-x)}\iff4x=-2(9-x)\\\\4x=-2\cdot9-2\cdot(-x)\\\\4x=-18+2x\ \ \ \ \ |subtract\ 2x\ from\ both\ sides\\\\2x=-18\ \ \ \ \ \ |divide\ both\ sides\ by\ 2\\\\\boxed{x=-9}$

$Use:\\a^{-n}=\left(\frac{1}{a}\right)^n\\\\\left(a^n\right)^m=a^{n\cdot m}\\\\\left(\frac{a}{b} \right)^n=\frac{a^n}{b^n}$

6 0

2 years ago

Read 2 more answers

Solve for c 6/15=2/c

saul85 [17]